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vampirchik [111]
3 years ago
12

A car moving at a speed of 20 m/s then accelerates uniformly at 1.8 m/s^2 until it reaches a speed of 25 m/s. What distance does

it travel during the time it is accelerating?
66 m
54 m
62 m
50 m
58 m

Physics
1 answer:
Volgvan3 years ago
8 0

Answer:

62.5 m

Explanation:

.......................................

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You run a race with your friend. At first you each have the same kinetic energy, but then you find that she is beating you. When
Blizzard [7]

Answer:

52.49 Kg

Explanation:

Let m1 and v1 denote your mass and velocity respectively

Let m2 and v2 denote your friends mass and velocity respectively

Kinetic energy is given by

KE= 0.5mv^{2}  

Since your kinetic energies are the same hence

0.5m1(v1)^{2}=0.5m2(v2)^{2}

m1(v1)^{2}=m2(v2)^{2} and making m2 the subject then  

m2=\frac { m1(v1)^{2}}{(v2)^{2}}

Since v2 is v1+0.28v1=1.28v1

Substituting m1 for 86 Kg

m2=\frac { 86 Kg(v1)^{2}}{(1.28v1)^{2}}= 52.49023\approx 52.49 Kg

3 0
3 years ago
Which wave, A or B, has higher energy?
eduard

Answer:

Wave A.

Explanation:

The energy of a wave is directly proportional to the square of the amplitude.

If a wave has higher amplitude, it will have more energy. On the other hand, a wave having lower amplitude, it will have less eenergy.

In this case, we need to tell which wave has higher energy. Hence, the correct option is A because it has a higher amplitude.

8 0
2 years ago
Read 2 more answers
The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that
pav-90 [236]

Answer:

The permittivity of rubber is  \epsilon  = 8.703 *10^{-11}

Explanation:

From the question we are told that

     The  magnitude of the point charge is  q_1 =  70 \ nC  =  70 *10^{-9} \  C

      The diameter of the rubber shell is  d = 32 \ cm  =  0.32 \ m

       The Electric field inside the rubber shell is  E =  2500 \ N/ C

The radius of the rubber is  mathematically evaluated as

              r =  \frac{d}{2} =  \frac{0.32}{2}  =  0.16 \ m

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

         E =  \frac{Q}{ \epsilon }  *  \frac{1}{4 *  \pi r^2}

Where \epsilon is the permittivity of rubber

    =>     E  *  \epsilon  *  4 * \pi *  r^2 =  Q

   =>      \epsilon  =  \frac{Q}{E *  4 *  \pi *  r^2}

substituting values

            \epsilon  =  \frac{70 *10^{-9}}{2500 *  4 *  3.142 *  (0.16)^2}

            \epsilon  = 8.703 *10^{-11}

7 0
3 years ago
A child pushes a 100 kg refrigerator with a force of 50 N, but the refrigerator does not move. Suppose the coefficient of static
faust18 [17]

Answer:

50 N

Explanation:

Since the refrigerator doesn’t move, that means the force of friction equals the amount of force the child exerts on the fridge. If the friction force were greater than the force by the child, the fridge would start accelerating towards the child. If it were less than the force the child exerted, the fridge would start accelerating away from the child. Therefore, the net force must be 0, in this case, the friction force is equal to the force the child exerted, for it to stay at rest (as Newton’s First Law stated).

I hope this helps! :)

8 0
2 years ago
On his way off to college, Russell drags his suitcase 19 m from the door of his house to the car at a constant speed with a hori
Mashcka [7]

Answer:

The work done on the suitcase is, W = 1691 J

Explanation:

Given data,

The force on the suitcase is, F  = 89 N

The distance Russell dragged the suitcase, S = 19 m

The work done on the suitcase by Russell is equal to the work done on the suitcase to overcome the friction

The work done on the suitcase by Russell is given by the formula

                          W = F · S

Substituting the given values,

                           W = 89 N x 19 m

                           W = 1691 J

Hence, the work done on the suitcase is, W = 1691 J

8 0
3 years ago
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