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Vedmedyk [2.9K]
3 years ago
10

PLEASE HELP I NEED THIS TO PASS THE EIGHTH GRADE AND I ONLY HAVE A COUPLE HOURS LEFT!!!!!!

Physics
1 answer:
zavuch27 [327]3 years ago
7 0

Answer:

the pe at the top of the building: 784 J

the pe halfway through the fall: 392 J

the pe just before hitting the ground: 784 J

Explanation:

Pls brainliest me

I had this question before

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A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i
sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, v_{Ci}=25\ m/s

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0
3 years ago
When you rub two balloons on your sleeve, does it have positive or negative?
igomit [66]

When you rub the balloons, it will take electrons away, which is negative. So, the balloons are negative
6 0
3 years ago
Read 2 more answers
) A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. What is the magnitude of the f
Yuri [45]

The frictional force required is 9000 N

Explanation:

In order to keep the car in the turn in circular motion without sliding, the frictional force must provide the centripetal force necessary for the circular motion.

Therefore, we can write:

F_f = m \frac{v^2}{r}

where the term on the left is the frictional force while the term on the right is the centripetal force, and where:

m is the mass of the car

v is its speed

r is the radius of the curve

For the car in this turn, we have

m = 1000 kg

v = 30 m/s

r=\frac{0.20 km}{2}=0.10 km = 100 m (since the diameter is 0.20 km, the radius is half that value)

And substituting, we find

F_f = (1000) \frac{30^2}{100}=9000 N

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

8 0
4 years ago
How do you do this?Or what are the formulus
LuckyWell [14K]
You got the formulas on the sheet on the top :) So just use those, exchanging v (as in velocity, expressed in m/s) and the d (in meters) and t (in seconds). Hope you will manage it.
4 0
3 years ago
a student does 100 j of work on the handle of a bicycle pump. the pump does 40 j of work pushing the air into the tire. what is
nalin [4]

Answer:

40%

Explanation:

Student -> Pump = 100j

Pump -> Tire = 40j

Between the two, 60j of energy were lost.

Efficiency = 40/100 = 40%

4 0
3 years ago
Read 2 more answers
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