-1 Let's say the set of downs starts at the 20 yard line (maybe the kicking team kicked deep, the receiving team took a knee and so play starts at the 20).
Ok - we're at the 20. First down - they advance 5 yards. So we're now at the 25. We can write that mathematically as:
20
+
5
=
25
So the second play they get sacked deep and lose 6 yards. So we subtract 6:
25
−
6
=
19
So what's the change in yardage for the 2 plays? We are on the 19 and started at the 20, so we can write:
19
−
20
=
−
1
and this makes sense because we know we advanced 5 and fell back 6
Answer:
y = 1/4 x - 1/2
Step-by-step explanation:
Remark
The general equation for a line is y = mx + b
You know that m = 1/4. The problem is what do you do about (2,0)?
Solution
y = 1/4 x + b Let x = 2 when y = 0
0 = 1/4 * 2 + b multiply 2 * 1/4
0 = 1/2 + b Subtract 1/2 from both sides
b = - 1/2
equation y = 1/4 x - 1/2
Graph
Here is the comparision
Purpose:To compare the topologic features of acute primary angle-closure glaucoma eyes before an attack to those of normotensive eyes, assuming that untreated fellow acute primary angle-closure glaucoma eyes are candidates for an acute attack.
Methods:Under dark-room conditions, ultrasound biomicroscopy was used to examine 50 eyes (12 fellow eyes of acute primary angle-closure glaucoma and 38 normotensive cases with a closure-possible narrow angle). Before any surgical or laser intervention, all eyes were examined and found to have normal pupillary response without the use of any topical drugs. Each eye was examined at four predetermined angle locations. The chamber angle configuration parameters were measured and compared between the two groups.
Result:Appositional angle closures were detected in 27 fellow eyes and 48 normotensive eyes with a closure-possible narrow angle. The incidence differed statistically between the two groups (69.2% in fellow eyes and 48% in normotensive eyes). In the fellow eye group, appositional angle closures beginning at the angle's entrance were more frequently detected. The distance between the iris root and the bottom of the angle varied significantly between groups.
Conclusion:Acute primary angle-closure glaucoma fellow eyes have different topologic features than normotensive narrow-angled eyes, as well as a higher incidence of appositional closure, which may predispose these eyes to an impending acute attack.
Learn more about glaucoma here:
brainly.com/question/1318395
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There is a system glitch during the process of adding my answer here so i create a document file for the answer, you find it in the attachment below.
Given:
There exist a proportional relationship between x and y.
To find:
The equation which represents a proportional relationship between x and y.
Solution:
If there exist a proportional relationship between x and y, then
where, k is constant of proportionality.
We know that, proportional relationship passes through the origin because (0,0) satisfy .
For x=0, check which equation has y=0.
In option A, 
.
In option B, 
.
In option C, 
.
In option D, 
Only in option C, we have a equation of the form with 4 as constant of proportionality and it passes through (0,0).
Therefore, the correct option is C.
