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1 year ago

Can someone help me please

Mathematics

1 answer:

Dafna1 [17]1 year ago

8 0

Answer:

B) -4, - 1, 2, 5, 8

Step-by-step explanation:

Hope it helps you in your learning process

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Identify the vertex of the function graphed below.

saw5 [17]

(3,-2) is the vertex

7 0

2 years ago

What is the answer to 6(1+8n)=-39+3n

MissTica

For this case we must simplify the following expression:

$6 (1 + 8n) = - 39 + 3n$

We apply distributive property on the left side of the equation:

$6 * 1 + 6 * 8n = -39 + 3n\\6 + 48n = -39 + 3n$

We subtract 3n from both sides of the equation:

$6 + 48n-3n = -39\\6 + 45n = -39$

We subtract 6 from both sides of the equation:

$45n = -39-6\\45n = -45$

We divide between 45 on both sides of the equation:

$n = \frac {-45} {45}\\n = -1$

Answer:

$n = -1$

5 0

3 years ago

If 1 card is drawn at random from a standard 52-card deck, what is the probability that the card drawn is a king?

Ahat [919]

Answer:

1/13 chance or roughly 7.7% chance.

Step-by-step explanation:

There are 4 Kings in a standard 52-card deck. If one King was to be pulled out, you'd get a probability of 4/52 chance of pulling a king. Simplified, 4/52 is 1/13 chance.

5 0

3 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

On a particular map, 1 inch represents an actual distance of 2.5 miles. the actual area of a lake is 12 square miles. find the a

Anton [14]

We have that
scale factor=1 in/2.5 miles
<span>the actual area of a lake is 12 square miles

</span>we know that
[area on the map]=[scale factor]²*[area actual]
[area on the map]=[1/2.5]²*[12]-----> 1.92 in²

the answer is
1.92 in²

5 0

3 years ago