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gizmo_the_mogwai [7]
2 years ago
14

A real estate builder wishes to determine how house size (House) is influenced by family income (Income), family size (Size), an

d education of the head of household (School). House size is measured in hundreds of square feet, income is measured in thousands of dollars, and education is in years. The builder randomly selected 50 families and ran the multiple regression. The business literature involving human capital shows that education influences an individual’s annual income. Combined, these may influence family size. With this in mind, what should the real estate builder be particularly concerned with when analyzing the multiple regression model?
Mathematics
1 answer:
creativ13 [48]2 years ago
8 0

When analyzing the multiple regression model, the real estate builder should be concerned with Multicollinearity.

<h3 /><h3>What is Multicollinearity?</h3>

This is a phenomenon in regression analysis where some of the independent variables are correlated. This can present an issue because the correlation leads to less reliable results.

The income in this research is influenced by the education and they both influence family size. There is therefore an issue of multicollinearity here because some variables are correlated.

Find out more on Multicollinearity at brainly.com/question/16021902.

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Given that the slope is -4 and the y intercept is -4 what is the equation of the line?​
Sloan [31]

Answer:

y=-4x-4

Step-by-step explanation:

y=-4x-4

y=mx+b where m=slope and b=y-intercept.

6 0
2 years ago
Write an expression for the sequence of operations described below.
Anna [14]

Answer:

a - (6-9)

Hopefully this is correct

Step-by-step explanation:

3 0
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(5x)/7 - x/14 = 9/7 solve for the unknown value this is a linear equation​
Ahat [919]

Step-by-step explanation:

\longmapsto \rm \dfrac{5x}{7} - \dfrac{x}{14} = \dfrac{9}{7} \\

\longmapsto \rm  \dfrac{10x + x}{14} = \dfrac{9}{7} \\

\longmapsto \rm  \dfrac{11x}{14} = \dfrac{9}{7} \\

→ 11x(7) = 14(9)

→ 77x = 126

→ x = 126 ÷ 77

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7 0
3 years ago
A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per
Tems11 [23]

Answer:

The pressure is changing at \frac{dP}{dt}=3.68

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} and we want to find at what rate is the pressure changing.

The equation that model this situation is

PV^{1.4}=k

Differentiate both sides with respect to time t.

\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)

Apply this rule to our expression we get

V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0

Solve for \frac{dP}{dt}

V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}

when P = 23 kg/cm2, V = 35 cm3, and \frac{dV}{dt}=-4 \:{\frac{cm^3}{min}} this becomes

\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68

The pressure is changing at \frac{dP}{dt}=3.68.

7 0
3 years ago
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inessss [21]

Answer:

1                  

-------------  

(x+2)(x-4)

Step-by-step explanation:

x+4                    x+3

-------------   * --------------

x^2+5x+6        x^2 -16

Factor

x+4                    x+3

-------------   * --------------

(x+3)(x+2)        (x+4)(x-4)

Cancel like terms

1                  1

-------------   * --------------

(1)(x+2)        (1)(x-4)

1                  

-------------    x cannot equal -3, -4, -2, 4  

(x+2)(x-4)

5 0
3 years ago
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