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yKpoI14uk [10]
2 years ago
12

Which expression could represent the phrase shown? (1 point)

Mathematics
1 answer:
ivolga24 [154]2 years ago
4 0

Answer:

(6 - 2) / 3

Step-by-step explanation:

First, use parenthesis to declare that whatever is inside will be done first. This is saying to subtract 2 from 6. Next, add / 3 after to show you are dividing the answer of 6-2 by 3.

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Lemaitre (based on Hubble's observations) was the first to suggest the _____.
Molodets [167]
Universe exploded into existence 
6 0
3 years ago
Read 2 more answers
The sum of 5 consecutive odd numbers is 145
xeze [42]

The sum of 5 consecutive odd integers is 145. These are the other 4 consecutive odd numbers. Now if we add all of these up we will get this : 25 + 27 + 29 + 31 + 33 = 145.

Hope I helped! ☺☼

8 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

6 0
3 years ago
The school's basketball team lost 4 times as many games as they won. They also tied 5 fewer games than they won.
jekas [21]
Let w won games, t tied games, s lose games

s=4w

t=w-5

s+t+w=43

4w+(w-5)+w=43

6w=48

w=7

s=4*7=21 games lost
7 0
3 years ago
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