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Elden [556K]
2 years ago
14

What do you think might be different between fat molecules and carbohydrate and protein molecules?

Chemistry
2 answers:
dimulka [17.4K]2 years ago
7 0

Answer:

Long answer

Proteins are the building blocks of the body, each and every organ muscle and skin and cells are made of proteins. They can also be used for providing energy to the body in a state where other energy sources aren't available.

Fats are stored energy blocks which can be used by the body at its own convenience whenever there is a deficit of energy in the body. They can also be directly burnt to give energy in cases where energy needs of the body are not met by dietary intake

Carbohydrates are the most convenient and preferable source of energy in the body and are easily converted to give out immidiate energy to the body, excess carbohydrates can be converted into fats and stored for later usage as and when required by the body.

Proteins, fats and carbohydrates have many secondary functions and roles in the human body. If you are keen to know anything more specific feel free to ask.

<h3>Short answer :</h3>

Fats are used for energy after they are broken into fatty acids. Protein can also be used for energy, but the first job is to help with making hormones, muscle, and other proteins.

Elina [12.6K]2 years ago
4 0

Answer:

Most Nutrients are digested into easy and simpler compounds. Carbohydrates are used for energy . Fats are used for energy after they are broken into fatty acids. Protein can also be used for energy, but the first job is to help with making hormones, muscle, and other proteins.

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Why do many people have different habits
Lady bird [3.3K]

Answer:

Explanation:

Porque la vida, nuestra vida,  está controlada de manera muy importante por nuestros hábitos, los cuales influyen, de forma, aunque inconsciente en por ejemplo: nuestra salud, productividad, seguridad económica y, como resultado, también en nuestra felicidad. En resumen, en todo y a todos  los que nos rodean.

3 0
3 years ago
Can someone help me with this question ASAP
Mkey [24]
Aye i can’t see the full question dawg, you gotta send a full picture of it
6 0
3 years ago
Which of the following wouldn't be a good tool to use when measuring pH values of solutions?
aev [14]

litmus paper

Because it will just tell if the solution is acidic or basic, it won't tell the pH

4 0
3 years ago
Read 2 more answers
Determine the freezing point of an aqueous solution containing 10.50 g of magnesium bromide in 200.0 g of water.
Rudiy27
For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:

                                ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where: 
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3

Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol

m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg


For the problem, 
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf

Tf = -1.59 celsius
5 0
4 years ago
Can someone please help me with this asap <br><br>what is the value of d<br>​
Stella [2.4K]

The value of "d" is 80°

Explanation:

Cyclic quadrilaterals are the special group of quadrilaterals with all its base lying on the circumference of the circle. In other words, a quadrilateral inscribed in a circle is called a cyclic quadrilateral.

Cyclic quadrilateral are characterised by some special features such as

  • Sum of opposite angles of a cyclic quadrilateral is always a supplementary angle.
  • If one of the sides of a cyclic quadrilateral is produced, then the exterior angle so formed is always double of the corresponding interior angle.  

Using the property 1  

We find that since the quadrilateral is cyclic, opposite pairs must be supplementary

100° +∠D must be equal to 180°  

D=180° -100° =80°

7 0
3 years ago
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