Answer:
68.18%
Explanation:
The question asking for the percentage of sugar present in milk bar chocolate. To find the percentage of a certain molecule, you have to divide the mass of the molecule with the total mass of the product. The calculation will be:
sugar percentage = sugar weight / milk bar chocolate weight * 100%
sugar percentage = 7.5g / 11g * 100%= 68.18%
Answer:
(a) weight percent of Cu = 44.59%
(b) weight percent of Zn = 53.49%
(c) weight percent of Pb = 1.91%
Explanation:
Given: Alloy contains- Cu=93.1 g, Zn=111.7 g, Pb=4.0 g
Therefore, the total mass of the alloy (m) = mass of Cu (m₁) + mass of Zn (m₂)+ mass of Pb (m₃)
m= 93.1 g + 111.7 g + 4.0 g = 208.8 g
(a) weight percent of Cu = (m₁ ÷ m)× 100% = (93.1 g ÷ 208.8 g)× 100% =44.59%
(b) weight percent of Zn = (m₂ ÷ m)× 100% = (111.7 g ÷ 208.8 g)× 100% =53.49%
(c) weight percent of Pb = (m₃ ÷ m)× 100% = (4.0 g ÷ 208.8 g)× 100% =1.91%
<h3>
Answer:</h3>
56.25 mL
<h3>
Explanation:</h3>
We are given;
Molarity of Na₂CO₃ = 1.50 M
Mass of Na₂CO₃ = 3.975 g
We are required to calculate the volume of Na₂CO₃
Step by step explanation:
<h3>Step 1: Determining moles of Na₂CO₃</h3>
Molar mass of Na₂CO₃ = 106 g/mol
But; moles = Mass ÷ molar mass
Therefore;
Moles of Na₂CO₃ = 3.975 g ÷ 106 g/mol
= 0.0375 moles
<h3>Step 2: Calculating the volume of Na₂CO₃</h3>
Relationship between volume, moles and molarity is given by;
Molarity = Moles ÷ Volume
Thus;
Volume = moles ÷ Molarity
= 0.0375 mole × 1.5 M
= 0.05625 L
But; 1 L = 1000 mL
Therefore; Volume = 56.25 mL
Hence, the volume of Na₂CO₃ is 56.25 mL
Answer:
flooding
Explanation:
since heavy rainfall, if its greater than usual
this causes flooding
hope this helps:)