in essence it's just asking on getting the equation of that line in more or less slope-intercept form, hmmm well, it's a line, so all we need is two points to get it, hmmm let's see let's use the starting point and terminal point, so we know it goes through the origin, (0,0) and also goes through (1, 0.7), let's change 0.7 to a fraction, so its 7/10, ok, let's use those two points from it.
Answer:
Step-by-step explanation:
- <em>This is a cyclic quadrilateral (all vertices on the same circle)</em>
<u>Opposite angles are supplementary:</u>
- ∠A + ∠C = 180°
- ∠B + ∠D = 180°
<u>Find x:</u>
- x + 5 + x - 7 = 180°
- 2x - 2 = 180°
- 2x = 182°
- x = 91°
<u>Find D:</u>
- ∠D = x - 14°
- ∠D = 91° - 14° = 77°
<u>Find B:</u>
Answer:
The equation has two zeros because the discriminant is greater than 0.
Step-by-step explanation:
3x^2 – 7x + 4
a=3 b = -7 c=4
The discriminant is
b^2 -4ac
(-7)^2 - 4(3)(4)
49 - 48
1
Since the discriminant is greater than zero, there are two real solutions
4 unknowns needs 4 equations. I'll call the unknown numbers a,b,c,d in that order left to right.
4 + a = b
a + b = c
b + c = d
c + d = 67
let's use substitution to get rid to combine equations and get rid of variables.
If a + b = c then a = c - b
4 + (c - b) = b
4 + c = 2b
If b + c = d then b = d - c
4 + c = 2(d - c)
4 + c = 2d - 2c
4 + 3c = 2d
then we have c + d = 67 so c = 67 - d
4 + 3(67 - d) = 2d
4 + 201 - 3d = 2d
205 = 5d
d = 41
Should be easy now, subtract backwards.
67 - 41 = 26
41 - 26 = 15
26 - 15 = 11
15 - 11 = 4
4, 11, 15, 26, 41, 67
Answer:
4 and -4 are both the square roots of 16
Step-by-step explanation:
