Answer:
0.07215 = 0.072 to 3 d.p.
Step-by-step explanation:
Central limit theorem explains that the sampling distribution obtained from this distribution will be approximately a normal distribution with
Mean = population mean
μₓ = μ = 9.8 minutes
Standard deviation of the distribution of sample means = σₓ = (σ/√n)
σ = 12 minutes
n = sample size = 30
σₓ = (12/√30) = 2.191
Probability that a random sample of 30 overtime periods would have a (sample) mean length of more than 13 minutes
Required probability = P(x > 13)
Since we've established that this distribution of sample means approximates a normal distribution
We first standardize 13 minutes.
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (13 - 9.8)/2.191 = 1.46
Required probability
P(x > 13) = P(z > 1.46)
We'll use data from the normal probability table for these probabilities
P(x > 13) = P(z > 1.46) = 1 - P(z ≤ 1.46)
= 1 - 0.92785 = 0.07215
Hope this Helps!!!
Answer: Ian is 25 and craig is 20
Step-by-step explanation:
(45 - 5) /2 +5 to one of them
Happy New Year from MrBillDoesMath!
Answer:
i ^ (2n) = (i^2)^n = (-1)^n = -1 if n is odd and = 1 if n is even
i ^ (2n+1) = i^(2n)* i = -1 * i = -i if n is odd and = 1*i = i if n is even
Not sure if this answers your question but hopefully pushes you n the right direction.
Thank you,
MrB
Answer:
a) 0.71
b) 0.06
Step-by-step explanation:
We solve using Baye's Theorem
It is estimated that 88% of senior citizens suffer from sleep disorders and 7% suffer from anxiety. Moreover, 5% of senior citizens suffer from both sleep disorders and anxiety.
We have Two events
A and B
Events A = 88% of senior citizens suffer from sleep disorders
P(A) = 0.88
Event B = 7% suffer from anxiety
P(B) = 0.07
Moreover, 5% of senior citizens suffer from both sleep disorders and anxiety.
P(A and B) = 0.05
a)Given that a senior citizen suffers from anxiety, what is the probability that he or she also suffers from a sleep disorder? Round your answer to the nearest hundredth.
This is calculated as:
P(A and B)/P(B)
= 0.05/0.07
= 0.7142857143
Approximately = 0.71
B) Find the probability that a senior citizen suffers from anxiety, given that he or she has a sleep disorder. Round your answer to the nearest hundredth.
This is calculated as:
P(A and B)/P(A)
= 0.05/0.88
= 0.0568181818
Approximately = 0.06
I think it is the first one
hope this helps
