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Stolb23 [73]
2 years ago
15

What is the pH of 0.000519 M NaOH?

Chemistry
1 answer:
Softa [21]2 years ago
3 0

The pH of the sodium hydroxide (NaOH) solution at the given concentration of 0.000519 M is determined as 10.72.

<h3>What is pH of solution?</h3>

The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration  [H+] of the given solution.

Concentration of the basic solution, [OH⁻] = 0.000519

pOH = -log[OH⁻]

pOH = -log[0.000519]

pOH = 3.28

<h3>pH of the solution</h3>

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 3.28

pH = 10.72

Thus, the pH of the sodium hydroxide (NaOH) solution at the given concentration of 0.000519 M is determined as 10.72.

Learn more about pH here: brainly.com/question/26424076

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A solution is prepared by dissolving 0.7234 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq
marishachu [46]

Answer: The final molarity of the diluted oxalic acid solution is 0.0032 M

Explanation:

Molarity: It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.7234g}{90g/mol}=0.008moles

V_s = volume of solution in ml

Molarity=\frac{0.008\times 1000}{100.0}=0.08

To calculate the final molarity of the diluted oxalic acid solution

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of concentrated oxalic acid solution.

M_2\text{ and }V_2 are the molarity and volume of diluted oxalic acid solution.

We are given:

M_1=0.08\\V_1=10.00mL\\M_2=?\\V_2=250.0mL

Putting values in above equation, we get:

0.08\times 10.00=M_2\times 250.0\\\\M_2=0.0032M

Thus the final molarity of the diluted oxalic acid solution is 0.0032 M

8 0
3 years ago
In a distillation operation, the heat added to the boiler a) increases with increase in reflux ratio b) decreases with increase
Leni [432]

Answer:

a) increases with increase in reflux ratio

Explanation:

If we increase the reflux ratio, which can de defined as : L/D = Condesate back to column /distillate discarded from column, it means that we increase the amount of condensate back to column. So the reboiler load will increase and be maximum in case of Total reflux ratio. And as vapor load will be increased, diameter of column will be increased too.  

7 0
3 years ago
Write a nuclear equation to describe the neutron induced fission of Pu-239 to form Kr-89 and Ce-149 (this fission is induced by
zlopas [31]

Answer:

\rm 2_{0}^{1}\text{n} + \, _{94}^{239}\text{Pu} \longrightarrow_{36}^{89}\text{Kr} + \, _{58}^{149}\text{Ce} + \, 3_{0}^{1}\text{n}; three

Explanation:

If the fission is induced by two neutrons, the unbalanced equation is

2\rm _{0}^{1}\text{n} + \, _{94}^{239}\text{Pu} \longrightarrow_{36}^{89}\text{Kr} + \, _{58}^{149}\text{Ce} + \, x_{0}^{1}\text{n}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation .  

Balancing the superscripts, we get

2 + 239 = 89 + 149 + x

      241 = 238 + x

          x = 3

The balanced nuclear equation is

\rm 2_{0}^{1}\text{n} + \, _{94}^{239}\text{Pu} \longrightarrow_{36}^{89}\text{Kr} + \, _{58}^{149}\text{Ce} + \, \mathbf{3}_{0}^{1}\text{n}

\text{The fission produces } \boxed{\textbf{three}} \text{ neutrons}

4 0
3 years ago
What changes occur at the molecular level when ice cream melts and forms a liquid?
Gemiola [76]
When ice cream melts from solid to liquid, the motion of the molecules increases. This is because as the phase change moves from solid to liquid to gas, entropy increases which increases the probability of the molecules to collide and move in the system. This increase may be because of the increase in temp, probable cause of the melting of icecream.
3 0
3 years ago
Read 2 more answers
What is the percent mass oxygen in calcium carbonate (CaCo3)?
Gnoma [55]
  <span>Step 1 is to determine the mass of each part 
Mass of Ca is 40.08 g 
Mass of C is 12.01 g 
Mass of O is 16.00 x 3 = 48.00 g 
Step 2 is to determine the total mass of the compound 
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g 

Step 3 is to determine the % of each part using the following formula: 
Mass of part / total mass x 100 = 

40.08 / 100.09 x 100 = 40.04 % Ca 

12.01 / 100.09 x 100 = 12.00 % C 

48.00 / 100.09 x 100 = 47.96 % O 

Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :) 
40.04 
+12.00 
+47.96 
=100.00</span><span>
</span>
4 0
2 years ago
Read 2 more answers
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