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Stolb23 [73]
2 years ago
15

What is the pH of 0.000519 M NaOH?

Chemistry
1 answer:
Softa [21]2 years ago
3 0

The pH of the sodium hydroxide (NaOH) solution at the given concentration of 0.000519 M is determined as 10.72.

<h3>What is pH of solution?</h3>

The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration  [H+] of the given solution.

Concentration of the basic solution, [OH⁻] = 0.000519

pOH = -log[OH⁻]

pOH = -log[0.000519]

pOH = 3.28

<h3>pH of the solution</h3>

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 3.28

pH = 10.72

Thus, the pH of the sodium hydroxide (NaOH) solution at the given concentration of 0.000519 M is determined as 10.72.

Learn more about pH here: brainly.com/question/26424076

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In a sample of pure calcium fluoride of mass 15.0 g, 7.70 g of calcium is present. First convert the mass into number of moles as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass.

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n=\frac{7.70 g}{40 g/mol}=0.1925 mol

Similarly, molar mass of CaF_{2} is 78.07 g/mol thus, number of moles will be:

n=\frac{15.0 g}{78.07 g/mol}=0.1921 mol.

Thus, 0.1921 mol of CaF_{2} have 0.1925 mol of Ca, or 1 mole of CaF_{2} will have approximately 1 mole of Ca.

Now, mass of Ca needs to be calculated in 45.0 g of CaF_{2}. Converting mass into number of moles first,

n=\frac{45.0 g}{78.07 g/mol}=0.5764 mol

Thus, number of moles of Ca will also be 0.5764 mol, converting number of moles into mass,

m=n\times M=0.5764 mol\times 40 g/mol=23.06 g

Therefore, mass of Ca will be 23.06 g.

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