1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lutik1710 [3]
3 years ago
9

Which of the following interactions are generally considered to be unfavorable? Group of answer choices a)Interaction between Ly

s and Glu at neutral pH, assuming standard pKa values of Lys and Glu. b)Interaction between a backbone amino group and a side chain carbonyl group. c)Interaction between two alpha helices. d)Interaction between Arg and Lys side chains at a pH of 7, assuming standard pKa values for Arg and Lys.
Chemistry
1 answer:
Anarel [89]3 years ago
7 0

Answer:

d) Interaction between Arg and Lys side chains at a pH of 7, assuming standard pKa values for Arg and Lys.

Explanation:

Arginine and Lysine are basic amino acids. They play same role in various membrane proteins. They both have high aqueous values which give rise to high electrostatic interaction. The interaction is mainly in the cations of the side chains. They both are heterologous secreted proteins which plays role of metabolite.

You might be interested in
Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).A
Bond [772]

Answer:

The molar solubility of carbon dioxide gas is 4.662\times 10^{-6} M.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{liquid}

where,

K_H = Henry's constant = 3.50\times 10^{-2}mol/L.atm

p_{CO_2} = partial pressure of carbonated drink

p_{CO_2}=p\times \chi_{CO_2}

where = p = Total pressure = 0.400 atm

\chi_{CO_2} = mole fraction of CO_2=3.33\times 10^{-4}

p_{CO_2}=0.400 atm\times 3.33\times 10^{-4} =0.0001332 atm

Putting values in above equation, we get:

C_{CO_2}=3.5\times 10^{-2}mol/L.atm\times 0.0001332  atm\\\\C_{CO_2}=4.662\times 10^{-6} M

Hence, the molar solubility of carbon dioxide gas is 4.662\times 10^{-6} M.

8 0
3 years ago
The densities of gases a, b, and c at stp are 1.25 g/l, 2.86 g/l and 0.714 g/l, respectively. calculate the molar mass of each s
kicyunya [14]
The  molar  mass  of    a, b and  c at  STP is calculated  as  below

At  STP  T  is always=   273 Kelvin and ,P= 1.0 atm 

by  use of  ideal  gas  equation  that  is  PV =nRT
n(number   of moles) = mass/molar mass  therefore  replace   n  in  the  ideal   gas  equation

that  is Pv = (mass/molar mass)RT
multiply  both side  by molar  mass  and  then  divide  by  Pv  to  make  molar mass the  subject of the  formula

that is  molar  mass =  (mass x RT)/ PV

 density is always = mass/volume

therefore  by  replacing  mass/volume  in   the equation  by  density the equation
molar  mass=( density  xRT)/P  where R  =  0.082 L.atm/mol.K

the  molar mass  for  a
= (1.25 g/l  x0.082 L.atm/mol.k  x273k)/1.0atm = 28g/mol

the molar  mass of b
=(2.86g/l  x0.082L.atm/mol.k   x273  k) /1.0  atm  = 64  g/mol

the molar  mass of c

=0.714g/l  x0.082  L.atm/mol.K  x273 K) 1.0atm= 16 g/mol

therefore  the 
   gas  a  is  nitrogen N2   since 14 x2= 28 g/mol
   gas b =SO2  since  32 +(16x2)= 64g/mol
  gas c =   methaneCH4  since  12+(1x4) = 16 g/mol


8 0
3 years ago
When the water inside a living cell freezes, the ice crystals damage the cell. The wood frog is a unique creature that can survi
professor190 [17]
But i think its B but i need answer too
4 0
3 years ago
Which weather condition is NOT associated with warm fronts??
slavikrds [6]

Answer:

A Winter storm usually does not come with a warm fronthey warm front.

Explanation:

When the front passes over an area it means to change in the weather. Many. Many friends cause weather events such as rain thunderstorms gusty winds tornadoes and hurricanes.

5 0
2 years ago
The unit cell for cr2o3 has hexagonal symmetry with lattice parameters a = 0.4961 nm and c = 1.360 nm. If the density of this ma
IRINA_888 [86]

To calculate the packing factor, first calculate the area and volume of unit cell.

Area is calculated as:

A=6R^{2}\sqrt{3}

Here, R is radius and is related to a as follows:

R=\frac{a}{2}

Putting the value in expression for area,

A=6(\frac{a}{2})^{2}\sqrt{3}=1.5a^{2}\sqrt{3}

The value of a is 0.4961 nm

Since, 1 nm=10^{-7}cm

Thus, 0.4961 nm=4.961\times 10^{-8} cm

Putting the value,

Area=1.5(4.961\times 10^{-8}cm)^{2}\sqrt{3}=6.39\times 10^{-15}cm^{2}

Now, volume can be calculated as follows:

V=Area\times c

The value of c is 1.360 nm or 1.360\times 10^{-7} cm

Putting the value,

V=(6.39\times 10^{-15}cm^{2})\times (1.360\times 10^{-7} cm)=8.7\times 10^{-22}cm^{3}

now, number of atom in unit cell can be calculated by using the following formula:

n=\frac{\rho N_{A}V_{c}}{A}

Here, A is atomic mass of Cr_{2}O_{3} is 151.99 g/mol.

Putting all the values,

n=\frac{(5.22 g/cm^{3})(6.023\times 10^{23} mol^{-1})(8.7\times 10^{-22}cm^{3})}{(151.99 g/mol)}\approx 18

Thus, there will be 18 Cr_{2}O_{3} units in 1 unit cell.

Since, there are 2 Cr atoms and 3 oxygen atoms thus, units of chromium and oxygen will be 2×18=36 and 3×18=54 respectively.

The atomic radii of Cr^{3+} and O^{2-} is 62 pm and 140 pm respectively.

Converting them into cm:

1 pm=10^{-10}cm

Thus,

r_{Cr^{3+}}=6.2\times 10^{-9}cm

and,

r_{O^{2-}}=1.4\times 10^{-8}cm

Volume of sphere will be sum of volume of total number of cations and anions thus,

V_{S}=V_{Cr^{3+}}+V_{O^{2-}}

Since, volume of sphere is V=\frac{4}{3}\pi r^{3},

V_{S}=36\left ( \frac{4}{3}\pi (r_{Cr^{3+})^{3}} \right )+54\left ( \frac{4}{3}\pi (r_{O^{2-})^{3}} \right )

Putting the values,

V_{S}=36\left ( \frac{4}{3}(3.14) (6.2\times 10^{-9} cm)^{3}} \right )+54\left ( \frac{4}{3}(3.14) (1.4\times 10^{-8} cm)^{3}} \right )=6.6\times 10^{-22}\times 10^{-8}cm^{3}

The atomic packing factor is ratio of volume of sphere and volume of crystal, thus,

packing factor=\frac{V_{S}}{V_{C}}=\frac{6.6\times 10^{-22}cm^{3}}{8.7\times 10^{-22}cm^{3}}=0.758

Thus, atomic packing factor is 0.758.

6 0
3 years ago
Read 2 more answers
Other questions:
  • A sample of copper with a mass of 63.5g contains 6.02 x10^23 atoms calculate the mass of an average copper atom
    6·1 answer
  • How many formula units of CaCO3 are present in 4.72 n of calcium carbonate?
    6·1 answer
  • In the reaction between bromine and sodium, a bromine atom gains an electron. What ion is formed? Is the bromine oxidized, or is
    12·2 answers
  • Suppose a star is undergoing a nuclear reaction. What happens to the elements around the star as it begins to emit more and more
    6·2 answers
  • 2Ag + H2S ➞ Ag2S + H2
    6·2 answers
  • Covalent Compounds HAVE a positive (+) or negative (-) charge <br> True or false
    6·1 answer
  • In J.J. Thomson's plum pudding model of the atom, the plums represent
    6·1 answer
  • What else is produced during the combustion of propane, C3H8?
    7·1 answer
  • 2 examples of when scientists used space probe technology to find out more about comets.
    11·1 answer
  • What separates the inner planets from the outer planets in our solar system?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!