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lutik1710 [3]
3 years ago
9

Which of the following interactions are generally considered to be unfavorable? Group of answer choices a)Interaction between Ly

s and Glu at neutral pH, assuming standard pKa values of Lys and Glu. b)Interaction between a backbone amino group and a side chain carbonyl group. c)Interaction between two alpha helices. d)Interaction between Arg and Lys side chains at a pH of 7, assuming standard pKa values for Arg and Lys.
Chemistry
1 answer:
Anarel [89]3 years ago
7 0

Answer:

d) Interaction between Arg and Lys side chains at a pH of 7, assuming standard pKa values for Arg and Lys.

Explanation:

Arginine and Lysine are basic amino acids. They play same role in various membrane proteins. They both have high aqueous values which give rise to high electrostatic interaction. The interaction is mainly in the cations of the side chains. They both are heterologous secreted proteins which plays role of metabolite.

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Identify the arrows that show removal of thermal energy when matter changes state.
BARSIC [14]
When matter loses heat, one of the following happens:
Liquid changes to solid (freezing), or
Gas changes to liquid (condensation), or
Gas changes to solid (deposition)

1- Freezing: when the temperature of a liquid matter drops below its freezing point, the liquid usually solidifies forming crystals. Example of this is when water changes to ice
2- Condensation: when the temperature of gas is reduced, the molecules slow down and come together changing the matter into liquid. Example of this is when water vapor condenses into water droplets.
3- Deposition: Sometimes when the temperature of a gas drops, it solidifies directly without passing through the liquid phase. An example of this is when water vapor changes directly to ice in sub-freezing areas without passing through the liquid phase. This is the process through which clouds are formed.
The diagram below shows these three changes in matter. 

6 0
4 years ago
PLEASE HELP
otez555 [7]

Answer:

P2≈393.609Kpa so I think the answer is 394 kPa

Explanation:

PV=mRT Ideal Gas Law

m and R are constant because they dont change for the problem. That means

PV/T=mR = constant

so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.

So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)

P2 = 393609 Pa

5 0
3 years ago
Read 2 more answers
What color does copper produce when it reacts to chlorine
kiruha [24]

The color it produces is Bright green.

6 0
3 years ago
Pamela wants to learn more about the career preferences of students in her school. She interviews a number of students from the
Viktor [21]
It is too early for students to have career preferences while still in school

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4 0
4 years ago
Think about the lab procedure you just read. Label each factor below with V for “variable” or C for “constant”.
luda_lava [24]
<h2>Answer:</h2><h3>The temperature of the gas: V</h3>

The temperature of gas is a variable quantity. It can be changed by changing energy or pressure of gas.

<h3>The amount of gas in the tube (in terms of mass and moles): C</h3>

It is a constant entity. As mass of gas once taken can not be changed by changing temperature, pressure etc.

<h3>The radius of the tube: C</h3>

The radius of tube cannot change at any rate.

<h3>The temperature of the gas (changed by the water surrounding it):  V</h3>

It can be changed by changing the temperature of water surrounding it.

<h3>The type of gas: C</h3>

It can never be changed.

<h3>The pressure of the gas: V</h3>

It can be changed by simply changing temperature and volume of gas.

8 0
4 years ago
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