For the purpose we will here use t<span>he ideal gas law:
p</span>×V=n×R×<span>T
V= </span><span>5.0 L
T= </span><span>373K
p= </span><span>203kPa
</span><span>
R is </span> universal gas constant, and its value is 8.314 J/mol×<span>K
</span>
Now when we have all necessary date we can calculate the number of moles:
n=p×V/R×T
n= 203 x 5 / 8.314 x 373 = 0.33 mole
The three parts are vacuole , cell wall , chloroplast
CaI₂ + Hg(NO₃)₂ --------->HgI₂ + Ca(NO3)2
2Al + 3Cl₂ --------->2AlCl3
Ag + HCl ------->AgCl + H2
C2H2 + 5O2 --------> 4CO2 + 2H2O
MgCl₂ --------->Mg + Cl2
Answer:
P1V1/T1 = P2V2/T2
Explanation:
- Hope that helped! Let me know if you need further explanation. Sorry I didn't give you exaxt one, it was kinda hard to read, but that is the correct answer I put above.
Answer:
0.0613 L
Explanation:
Given data
- Initial pressure (P₁): 1.00 atm
- Initial volume (V₁): 1.84 L
- Final pressure (P₂): 30.0 atm
Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 1.00 atm × 1.84 L / 30.0 atm
V₂ = 0.0613 L
