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LekaFEV [45]
3 years ago
5

Name three parts of a plant cell that are not found in an animal cell

Chemistry
1 answer:
lions [1.4K]3 years ago
4 0
The three parts are vacuole , cell wall , chloroplast
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NaClO3 &gt; NaCl + O2 <br> Balance
tiny-mole [99]

Answer:

Balancing Strategies: To balance this reaction it is best to get the Oxygen atoms on the reactant side of the equation to an even number. Once this is done everything else falls into place. Put a "2" in front of the NaClO3. Change the coefficient in front of the O2.

6 0
2 years ago
Anybody know chemistry Grahams law ?
sukhopar [10]
There is two different types but i’ll just do both meanings just incase.

Graham's Law of Diffusion: the rate of diffusion of one gas through another is inversely proportional to the square root of the density of the gas.

Graham's Law of Effusion: the rate of effusion of a gas is inversely proportional to the square root of the density of the gas.

hopes this helps..!
7 0
3 years ago
When ionic compounds are added to water, they dissociate or break apart into ions. In the case of table salt, salt added to wate
Lostsunrise [7]

Answer:

b dissociate

Explanation:

5 0
3 years ago
When an electron falls from an excited state to ground state, is energy released or absorbed?
strojnjashka [21]

Answer:

Energy is released.

Explanation:

When an electron absorbs energy, it moves up into an excited state. When it releases energy, it will return to the ground state.

5 0
3 years ago
The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
zimovet [89]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

P (Half-life) = 10.0 minutes

T (Elapsed time for sample reduction) = 25.9 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

m \approx \dfrac{53.3}{6.021}

\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

3 0
3 years ago
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