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2 years ago

Please help, I lost my previous tutor just when she was explaining the answer

Chemistry

1 answer:

TEA [102]2 years ago

5 0

Answer:

HCO₂/H₂O is not the acid-base conjugate pair.

Explanation:

<em>Acid and conjugate base pairs differ by an H+ ion.</em>

Neither HCO₂ nor H₂O has lost or gained protons.

The conjugate acid of H₂O is H₃O⁺

The conjugate base of HCO₃⁻ is CO₃²⁻

[A conjugate acid has one more H⁺ than its base]

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Explanation:

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3 years ago

Two hydrogen atoms collide in a head on collision and end up with zero kinetic energy. Each then emits a photon of 121.6 nm (n=2

Zinaida [17]

Explanation:

Expression for the kinetic energy is as follows.

K.E = $\frac{1}{2}mv^{2}$

Now, total kinetic energy will be as follows.

K.E = $2 \times \frac{1}{2}mv^{2}$ = $m \times v^{2}$

Since, this energy converts into electromagnetic radiation of wavelength 121.6 nm.

Relation between energy and photon is as follows.

Energy of photon = $\frac{hc}{\lambda}$

= $\frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{121.6 \times 10^{-9}}$

= $1.63 \times 10^{-18} J$

$m \times v^{2} = 1.63 \times 10^{-18}$

v = $\sqrt{\frac{1.63 \times 10^{-18}}{1.67 \times 10^{-27}}$

= $3.12 \times 10^{4}$ m/s

Thus, we can conclude that atoms were moving at a speed of $3.12 \times 10^{4}$ m/s before the collision.

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4 years ago

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avanturin [10]

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3 years ago

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Explanation:

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Answer:

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3 years ago