Answer:
The forward reaction is occurring at a faster rate than the reverse reaction.
Explanation:
Reaction quotient (Q) of the given reaction is -
![Q=\frac{[NO]^{2}}{[N_{2}][O_{2}]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BNO%5D%5E%7B2%7D%7D%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D)
where [NO], ![[N_{2}]](https://tex.z-dn.net/?f=%5BN_%7B2%7D%5D)
and ![[O_{2}]](https://tex.z-dn.net/?f=%5BO_%7B2%7D%5D)
represents concentrations of respective species at a certain time.
Here = 0.80 M, = 0.050 M and [NO] = 0.10 M
So, 
Hence 
It means that forward reaction is faster than reverse reaction at that point. Because then only concentration of NO is higher than concentrations of and which makes Q higher than K.
- Telleurium ( Te) is the chemical symbol
- electron is 52,
- there are 2 electron in 5s
A drop of iquid mercury is D. <span> a pure substance and an element. This is because mercury is an element which exists as liquid in the normal or standard conditions. It is a metal that is toxic to all environments. It is pure because it is composed only of one kind of substance.</span>
<span>Bleach and ammonia can be used to make cl2. Bleach is commercially available and so people should be very careful during these experiments or even when mixing things in the household.</span>
The range is negative numbers.
The interval for the range is .
***You might want to look at your functions again because I don't see a choice that matches.
Step-by-step explanation:
Given functions:
We are asked to find the range of .
I'm also going to look at the domain just to see if this possibly might change my range .
is the inner function. So we will consider the domain of that function first.
You only have to worry about division by zero for the function .
Since we are dividing by , we don't want to be zero.
So far the domain is all real numbers except .
Now let's move out.
exists for all numbers, . So we didn't want to include from before.
Now let's put it together:
So the domain is still all real numbers except at since we cannot divide by 0 and is 0 when .
with .
is positive for all numbers except .
So is negative for all numbers since negative divided by positive is negative.
So the range is only negative numbers.
Let's also look at the inverse:
Multiply both sides by :
Divide both sides by :
Take the square root of both sides:
.
So can't be 0 and it also can't be positive because the inside of the square root will be negative (since negative divided by positive results in negative).
