HCI is one of the most common acids out of the following
Answer:
Two factors that might have a affect of which copper sulphate mineral will occur at a given location is:
A. Copper sulphate high solubility in water
B. Also it binds nicely with the sediments or the crystal.
Explanation:
As it is mentioned here that copper sulphate can be crystallized as an anhydrate which means that their is no waterin those crystals or can be as of those three different hydrates whose crystal structure varies with the amount of water present in it.
The four forms are also given of the copper sulphate are:
- Bonatite
- Boothite
- Chalcanthite
- Chalcocyanite
So, the two factors that might give an affect which type of copper sulphate mineral willoccur at a given location is:
A. The copper sulphate high solubility in water.
B. It binds extremely nicely with the sediments or say to the crystal. It is also regulated by plants.
<u>Answer:</u> The molality of magnesium chloride is 1.58 m
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (magnesium chloride) = 75.0
= Molar mass of solute (magnesium chloride) = 95.21 g/mol
= Mass of solvent = 500.0 g
Putting values in above equation, we get:
Hence, the molality of magnesium chloride is 1.58 m
Answer:
It is made up of two elements.
Explanation:
To answer the question given above,
We shall determine the number of elements present in CaCl₂. This can be obtained as follow:
CaCl₂ contains calcium (Ca) and chlorine gas (Cl₂).
This implies that CaCl₂ contains two different elements.
Now, considering the options given in the question above, CaCl₂ is made up of two elements.
Answer:
Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
Explanation:
Let's apply the formula for freezing point depression:
ΔT = Kf . m
ΔT = 74.2°C - 73.4°C → 0.8°C
Difference between the freezing T° of pure solvent and freezing T° of solution
Kf = Cryoscopic constant → 5.5°C/m
So, if we replace in the formula
ΔT = Kf . m → ΔT / Kf = m
0.8°C / 5.5 m/°C = m → 0.0516 mol/kg
These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg
0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:
Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
