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Dmitrij [34]
2 years ago
15

Diethylene glycol is an organic compound used as a fuel in heating cans. Based on its structure and your data recorded in Data T

able 3, how do you hypothesize its energy efficiency (cal/g) compared to isopropanol and paraffin wax?
Chemistry
1 answer:
Firdavs [7]2 years ago
7 0

Due to its higher oxygen content and based on its structure dietheylene glycol has a higher energy efficiency (cal/g) compared to isopropanol and paraffin wax.

<h3>What is the calorific value of a fuel?</h3>

The calorific value of a fuel is the amount of heat energy released from the combustion of the fuel under standard conditions.

Dietheylene glycol, isopropanol and paraffin wax are all used as fuels.

However, due to it higher oxygen content and based on its structure, diethethylene glycol has a higher calorific value than either isopropanol or paraffin wax.

Therefore, dietheylene glycol has a higher energy efficiency (cal/g) compared to isopropanol and paraffin wax.

Learn more about calorific value at: brainly.com/question/12975147

#SPJ1

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Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

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Exemplificati solutii in care solventul este gaz
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Sper că vă ajută:)I hope it helps:)

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