A telephone pole is 24 feet tall. Curtis, who is standing some distance away from the telephone pole measures the angle of eleva tion to the top of the pole as 51.4 degrees. How far away from the base of the telephone pole is Curtis standing if Curtis's eye height is 5.2 feet?
1 answer:
The distance from the base of the telephone pole to Curtis is about 15 feet.
<h3>What is an
equation ?</h3>
An equation is an expression t hat shows the relationship between two or more number and variables.
Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.
Let d represent the distance from the base of the telephone pole to Curtis, hence:
tan(51.4) = (24 - 5.2) / d
d = 15 feet
The distance from the base of the telephone pole to Curtis is about 15 feet.
Find out more on equation at: brainly.com/question/2972832
#SPJ1
You might be interested in
This question is worded slightly strangely but I believe I understand it.
<u>1.38</u> as a fraction is <em>138/100</em> .
Divide by 100. 350/100=3.5 which is 3 and 1/2
We have to multiply given (3-2i)(3+2i)
