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ycow [4]
2 years ago
8

8.3 miles of sodium chloride in 0.65 of water.

Chemistry
1 answer:
Allisa [31]2 years ago
4 0

Answer:

12.77 M

Explanation:

8.3 moles of NaCl in .65 L of water ?    Looking for M ?

8.3 M / .65 L  =  12.77 M

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Which option explains how some parts of a plant can be white?
just olya [345]

Some parts of a plant can be white because they do not contain chlorophyll.

Chlorophyll is a term to refer to a characteristic compound of most plants that has the function of:

  • Bring the green color to vegetables
  • Take charge of the photosynthesis process.

Some plants do not have as much chlorophyll in their systems. However, this does not affect their reproduction and growth because they have developed other feeding methods through their roots.

These plants that contain low amounts of chlorophyll have pale and white colorations because chlorophyll is what gives the plants their intense green color.

Note: This question is incomplete because options are missing. Nevertheless, I can answer it based on my prior knowledge.

Learn more in: brainly.com/question/14884020

7 0
2 years ago
You have studied the gas-phase oxidation of HBr by O2: 4 HBr(g) + O2(g) → 2 H2O(g) + 2 Br2(g) You find the reaction to be first
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Answer:

Explanation:

FIND THE SOLUTION IN THE ATTACHMENT

4 0
3 years ago
Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te
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4 0
3 years ago
Calculate the ph of a 0.021 m nacn solution. [ka(hcn) = 4.9  10–10]
ohaa [14]

<span>Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN</span>⁻(aq) + Na⁺<span>(aq).
Chemical reaction 2: CN</span>⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻<span>(aq).
c(NaCN) = c(CN</span>⁻<span>) = 0.021 M.
Ka(HCN) =  4.9·10</span>⁻¹⁰<span>.
Kb(CN</span>⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵<span>.
Kb = [HCN] · [OH</span>⁻] / [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] = x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M - x).
Solve quadratic equation: x = [OH</span>⁻<span>] = 0.00198 M.
pOH = -log(0.00198 M) = 2.70.
pH = 14 - 2.70 = 11.3.</span>

4 0
3 years ago
SO NOT HALAL MODE :(
amid [387]

Answer:

umm

Explanation:

5 0
3 years ago
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