The bond angles a and b are 120° respectively. The bond angle c is 111.4° .while the bond angle d is 120°. The bond angles e and f are 120° respectively.
In the carbonate ion, all the bond angles and bond lengths are equal hence three equivalent resonance structures can be drawn for the ion. All the bond angles, ( a and b) in carbonate ion all have bond angle of 120°.
The bond angle marked c in OCCl2 has a bond angle 111.4°, the bond angle marked d in the compound has the bond angle, 120°.
There are three bond angles present in the nitrate (NO3-) ion. Three resonance structures contribute to this bond. Based on these structures, the bond angles e and f in the molecule is 120°.
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Hello!
Understanding how much of a product is produced in a reaction is referred to as Stoichiometrically understanding the reaction.
Stoichiometry is the calculation of the quantitative relationships between reactants and products in a chemical reaction. The first to talk about stoichiometry was Jeremias Benjamin Ritcher, who said that "Stoichiometry is the science that measures the quantitative proportions or mass ratios of chemical elements that are involved in a chemical reaction".
To calculate how much of a product is produced in a reaction, Stoichiometry is used, applying the law of conservation of mass. That means that the amount of product can be calculated from the amounts of reactants if they are known.
Answer:
im not sure but I hope this helps
Explanation:
I believe the equivalents is just the moles reactant/moles limiting reactant
water has a denisty of 1 g/mL. 1 L is 1000 ml so there are 1000g/L.
the molar mass of water is 18g/mol if you use the Liters in the equation above you can find the number of grams present. divide this number you found by 18 to find the moles.
now take the amount of the other reactant given and divide it by its own molar mass. this will give you the number of moles of that reactant.
divide the moles of water by the moles of the reactant and that is the equivalent.
to find the normality you take this number and divide it by the number of liters.
Answer:
C 5 mol A; 6 mol B
Explanation:
eto po answer ko sana makatulong
Answer:
The answer to your question is C = 0.037 cal/g°C
Explanation:
Data
mass of the wire = m = 237 g
temperature 1 = T1 = 25°C
temperature 2 = T2 = 107°C
Heat = Q = 722 cal
Specific heat = C
Process
1.- Write the formula to find the specific heat
Q = mC(T2 - T1)
-Solve for C
C = Q / m(T2 - T1)
2.- Substitution
C = 722 / 237(107 - 25)
3.- Simplification
C = 722 / 237(82)
C = 722 / 19434
4.- Result
C = 0.037 cal/g°C
