All categories

3 years ago

Which actions are part of the dissolution process of an iconic solute in water?

Chemistry

1 answer:

ASHA 777 [7]3 years ago

3 0

Answer is: The ions in the solute separate from each other.

For example, dissociation of potassium iodide in water:

KI(aq) → K⁺(aq) + I⁻(aq).

Solvation is the interaction of solvent (water) with molecules or ions (in this example K⁺ and I⁻) in a solute.

Anion I⁻ has negative charge, so positive end (hydrogen atoms) of a water molecul attracts them.

You might be interested in

Please Answer! Help! Will Give Brainliest. Find Keq for a 3.0 L container with 1.2 moles of both NO2 and N2O4 initially and 0.38

Nuetrik [128]

Answer:

Kc → 41.9

Explanation:

This is the equilibrium:

2NO₂(g) ⇌ N₂O₄(g)

So the expression for Kc will be:

Kc = [N₂O₄] / [NO₂]²

We prospose the situations:

Initially we have 1.2 moles of NO₂ and N₂O₄

X amount has reacted. As stoichiometry is 2:1, we have produced x/2 of the product during the reaction

Finally In equilibrium we have, 0.38 NO₂

2NO₂(g) ⇌ N₂O₄(g)

Initially 1.2 1.2

React x x/2

Eq (1.2 - x) = 0.38 1.2 + x/2

As we have [NO₂] in the equilibrium, we can determine x (the amount that has reacted) to solve and determine, the [N₂O₄] in the equilibrium

1.2-0.38 = x → 0.82

1.2 + 0.82/2 = 2.02 → [N₂O₄]

For Kc, we need Molar concentration, so we have to divide [N₂O₄] and [NO₂] by the volume

[N₂O₄] → 2.02 mol/3L = 0.673 M

[NO₂] → 0.38 mol/3L = 0.127 M

Now we can replace the Kc expression:

Kc → [N₂O₄] / [NO₂]² → 0.673 / 0.127² = 41.9

Remember that Kc has no UNITS

6 0

3 years ago

Give the correct thermochemical equations for a (cacl2+h2o) pack and (nh4no3+h2o) pack.

UkoKoshka [18]

Explanation: A thermochemical equation is a balanced chemical equation which require an enthalpy change.

A balanced equation is the equation in which number of atoms on reactant side is same as the number of atoms on product side.

A thermochemical equation for $CaCl_2+H_2O$ is:

$CaCl_2+2H_2O\rightarrow Ca(OH)_2+2HCl+heat$

Here, heat is released in the reaction hence, it is a type of exothermic reaction.

A thermochemical equation for $NH_4NO_3+H_2O$ is:

$NH_4NO_3+heat\overset{water}{\rightarrow} NH_4^++NO_3^-$

Here, heat is absorbed in the reaction hence,it is a type of endothermic reaction.

3 0

3 years ago

A rocket has a power output of 55,000 ft.-lbs./sec. while raising a small satellite into orbit. How many horsepower is the rocke

IRINA_888 [86]

Answer:

Here is the answer: 100 H.P.

4 0

3 years ago

Read 2 more answers

This compound, (C10H12O3), shows strong, sharp absorption between 1700 and 1720 cm-1, and strong, broad absorption over the regi

Kruka [31]

Answer:

Explanation:

The peak at 1700-17200 cm⁻¹ in the infrared spectrum shows the existence of a carbonyl group (C=O). The appearance of an OH peak is shown by the broad peak at 2500-3000 cm⁻¹. The peak at 12.4 ppm in 1H NMR identifies the existence of carboxylic acid. The peaks at 6.78 ppm and 7.11 ppm suggest that the prevalence existence of a benzene ring in the molecule. Because these peaks are doublets, the benzene is being para-substituted.

The existence of the CH2 group is shown by the peak at 2.49 ppm, which integrates 2 hydrogens. Provided that the breaks are doublets, It would be bound to another CH2 molecule as well as carbon that is devoid of hydrogen (benzene carbon).

The existence of the CH2 group, which is linked to the above-listed CH2 group, is also demonstrated by the next peak at 2.8 ppm. It must be bonded with carbonyl carbon so it breaks as a doublet. As a result, it has a greater chemical transition. The CH3 category is shown by the peak at 3.72 ppm. Its chemical change is strong, indicating that CH3 is linked to an oxygen atom that is linked to benzene.

NMR details at 13C. Carbonyl carbon of acid has a high (peak) at 173.89 ppm. Benzene carbon peaks range from 113.55 to 157.87 ppm. The peak at 64 is made up of CH3, while the other two are made up of CH2.

The structure of the diagram is shown below with its degree of unsaturation.

3 0

3 years ago

M → Mt+e<br> Has M lost or gained an electron?

ohaa [14]

Answer:

M has lost an electron, one electron, and given it to Mt

Explanation:

4 0

2 years ago