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kirill [66]
3 years ago
9

The different phases of the Moon refer to A. Changes in the Moon's shape. B. Changes in the Moon's visibility. C. Changes in sea

sons on the Moon. D. Changes in the Moon's rotation.
Chemistry
1 answer:
Sav [38]3 years ago
5 0

Answer:

B. Changes in the Moon's visibility.

Explanation:

The moon's shifting of position makes it "appear" as being smaller or bigger. This is simply because the moon is rotating and the sun's light shines on a certain area of the moon, and depending on where we are on the Earth is how the moon looks or appears to our perspective.

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Why is the net charge of a neutral atom zero?
nikitadnepr [17]

Answer:

Explanation:

The positive (protons) and negative (electrons) charges balance each other in a neutral atom, which has a net zero charge. Because protons and neutrons each have a mass of 1, the mass of an atom is equal to the number of protons and neutrons of that atom.

6 0
3 years ago
Which of the following correctly describes the state of matter of one of the samples? D is a liquid because it retains its shape
Brut [27]
D is a solid because it retains its shape
7 0
3 years ago
What two substances are always produced by a neutralization reaction?
satela [25.4K]
What two substances are always produced by a neutralization reaction? water and salt
8 0
3 years ago
What is the mole fraction of HCl in a solution that contains 0.99 mole HCl and 3.6 mole H2O
marysya [2.9K]

Answer:

  0.216

Explanation:

The mole fraction of HCl is the number of moles of HCl (0.99) divided by the total number of moles in the solution.

  mole fraction = (0.99)/(0.99 +3.6) = 0.2157

The mole fraction of HCl is about 0.216.

4 0
3 years ago
The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o
Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

\frac{d[NO]}{dt} =21 torr/min

The balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

Rate change = (21 + 10.5) - 21 = 10.5 torr/min

Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

8 0
3 years ago
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