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djyliett [7]
2 years ago
11

The momentum of the moving depends on which among the given factors?

Physics
1 answer:
Tasya [4]2 years ago
4 0

Explanation:

<h3>mass and velocity</h3>

,,,,,

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When the ignition is first turned on a click noise is heard from under the hood of a vehicle equipped with ETC. Technician A say
Ierofanga [76]

Answer:

Technician A says that this is the normal operation of the ETC self -test is the correct answer.

Explanation:

An engine control unit (ECU), also widely referred to as an engine control module (ECM), is a type of electronic control device that controls an internal combustion engine with a series of actuators to ensure maximum engine performance.

It achieves so by reading values from a multitude of sensors within the engine bay, translating data using multidimensional feedback maps (the so-called lookup tables) and modifying the actuators.

Mechanically fixed and dynamically regulated by mechanical and pneumatic means, air-fuel combination, ignition time, and idle speed were before ECUs.

As soon as the system gets battery voltage, after ignition is turned, the efi computer makes a self-test of all the actuators and sensors, included the ETC.

4 0
3 years ago
The greatest pull of a magnet is near its poles.<br><br> True<br> False
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False because opposites attract. :)
6 0
2 years ago
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Which best compares a brush and a commutator in an electric motor?
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3 0
3 years ago
Read 2 more answers
1. Is The larger the mass the greater the acceleration is on a smaller object?
zheka24 [161]

Answer:No,a smaller object would have more acceleration because it would take less force to move.

7 0
2 years ago
A rock is thrown downward at a speed of 8.5 m/s and hits the ground 2.25 seconds later. From what height was the rock thrown? Wh
vekshin1

Answer:

The velocity and height is 31 m/s and 44.4 m respectively .

Explanation:

Given :

Initial speed of rock , u = 8.5 m/s .

Time taken to reach ground , t = 2.25 s .

Also , acceleration due to gravity is , g=10\ m/s^2 .

Now , to find the velocity when it hit ground .

Applying equation of motion :

v=u+at\\v=8.5+10\times 2.25\\v=31\ m/s

Also , height from which rock is thrown is given by :

h=ut+\dfrac{at^2}{2}\\\\h=8.5\times 2.25+\dfrac{10\times 2.25^2}{2}\\\\h=44.4\ m

Hence , this is the required solution .

7 0
3 years ago
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