Answer
given,
change in enthalpy = 51 kJ/mole
change in activation energy = 109 kJ/mole
when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.
where as activation energy of the product and the reactant decreases.
example:
ΔH = 51 kJ/mole
E_a= 83 kJ/mole
here activation energy decrease whereas change in enthalpy remains same.
D is the answer. It is a firm statement.
The force is 2.0 N east
Explanation:
The impulse exerted by a force is defined as the product between the force itself and the time interval during which the force is applied. Mathematically, it is equal to the change in momentum experienced by the object on which the force is acting:

Where
I is the impulse
F is the force
is the time interval during which the force is applied
is the change in momentum
In this problem,
is the time interval
(east) is the impulse
Therefore, the magnitude of the force is

And the direction is the same as the impulse (east).
Learn more about impulse and change in momentum:
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When conducting and experiment you want to have a notebook and something to write down notes with so you can keep everything organized and proper, and to not miss anything in the experiment. Also you want to have everything in order of the way it should be in.
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Supplementary angles add up to 180°.
If one is 40°, then the other is (180° - 40°) = 140° .
None of those choices describes a plane.
Choice 'C' is the only example of a plane.