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castortr0y [4]
3 years ago
14

A 24kg child descends a slide 5m high and reaches the bottom with a speed of 2.8m/s. How much thermal energy due to friction was

generated in this process?
Physics
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

1101.96 J

Explanation:

Potential energy at top = mgh = 24*10*5 = 1200J

Kinetic energy at bottom = 1/2*m*v² = 0.5*24*(2.8)²= 94.08 J

Loss of energy = 1200 J - 98.04 J

                         = 1101.96 J

Thermal energy due to friction =1101.96 J

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What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3
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This question is incomplete, the complete question is;

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|FI = |QQ'I / d²

where K = 1/4π∈0, and

∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

Consider two point charges located on the x-axis:

one charge, q₁ = -18.5 nC, is located at

x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

Explanation:

Given that;

Q₁ = -18.5 nC       Q₃ = 51 nC        Q₂ = 30.5 nC

x₁ = - 1.715m         x₃ = - 1.085m     x₂ = 0

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x - component of Net force on charge Q₃ is

(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²

(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

(Fnet3)x = -3.3287 × 10⁻⁵ N

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