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castortr0y [4]
3 years ago
14

A 24kg child descends a slide 5m high and reaches the bottom with a speed of 2.8m/s. How much thermal energy due to friction was

generated in this process?
Physics
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

1101.96 J

Explanation:

Potential energy at top = mgh = 24*10*5 = 1200J

Kinetic energy at bottom = 1/2*m*v² = 0.5*24*(2.8)²= 94.08 J

Loss of energy = 1200 J - 98.04 J

                         = 1101.96 J

Thermal energy due to friction =1101.96 J

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A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
fomenos

initial velocity of the car given as

v_i = 0

final velocity is given as

v_f = 108 km/h

as we know that

1 km/h = 0.277 m/s

now we can convert final speed into m/s

v_f = 108 * 0.277 = 30 m/s

now acceleration is rate of change in velocity

a = \frac{v_f - v_i}{t}

a = \frac{30 - 0}{10}

a = 3 m/s^2

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3 years ago
Relation of Kilometre and mile​
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2 years ago
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The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a
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The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\  I_2= 0.125 \ foot-candles

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

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brainly.com/question/26711747

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Answer:

Check explanation

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