Answer:
a.Beth
b.2232 s
Explanation:
We are given that
Distance,d=400 mi
Speed of Alan,v=45 mph
Speed of Beth,v'=55 mph
a.Time =
Using the formula
Time taken by Alan=
Time taken by Beth=
Alan will reach San Francisco at 4:53 PM
Beth will reach San Francisco at 4:16 PM
Beth will reach before Alan.
b.Difference between time=8.89-7.27=1.62 hr
t=1.62 hr
1.62-1=0.62 hr
0.62 hr=
Hence, Beth has to wait 2232 s for Alan to arrive .
The time elapsed is 9 seconds
Explanation:
The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:
where
:
v is the final velocity of the ball
u is the initial velocity
a is the acceleration
t is the time elapsed
For the ball in this problem, we have:
u = 3 m/s is the initial velocity
v = 34.5 m/s is the final velocity
is the acceleration
Solving for t, we find the time taken for this change in velocity:
Learn more about acceleration:
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Answer:
A) True
Explanation:
Researchers have detected numerous jets of gas ejected from poles of young stars and planetary nebulae.
By examining images of hydrogen molecules excited at infrared wavelengths, scientists have been able to see through the gas and dust in the Milky Way, in order to observe the most distant targets. These goals are normally hidden from view and many of them have never been seen before.
The entire study area covers approximately 1,450 times the size of the full moon, or the equivalent of an image of 95 gigapixels. The survey reveals jets emanating from proto-stars and planetary nebulas, as well as remnants of supernovae, the illuminated edges of vast clouds of gas and dust, and the warm regions that surround massive stars and their associated groups of smaller stars.
Katherine paid $1.25 for a bottle of water
Answer:
The time period of the motion is, T = 0.03 s
The frequency of the rotation is, f = 30 Hz
Explanation:
Given data,
The rotational speed of an object, ω = 30 rpm
ω = 188.5 rad/s
The time period of motion is,
T = 2π / ω
Substituting the given values in the above equation
= 2π / 188.5
T = 0.03 s
The time period of the motion is, T = 0.03 s
The frequency of rotation,
f = 1 /T
= 1 / 0.03
= 30 Hz
Hence, the frequency of the rotation is, f = 30 Hz
