What are two deposit s made by water

A spaceship whose rest length is 350m has a speed of .82c

igomit [66]

Answer:

$t'=1.1897*10^{-6} s$

t'=1.1897 μs

Explanation:

First we will calculate the velocity of micrometeorite relative to spaceship.

Formula:

$u=\frac{u'+v}{1+\frac{u'*v}{c^{2}}}$

where:

v is the velocity of spaceship relative to certain frame of reference = -0.82c (Negative sign is due to antiparallel track).

u is the velocity of micrometeorite relative to same frame of reference as spaceship = .82c (Negative sign is due to antiparallel track)

u' is the relative velocity of micrometeorite with respect to spaceship.

In order to find u' , we can rewrite the above expression as:

$u'=\frac{v-u}{\frac{u*v}{c^{2} }-1 }$

$u'=\frac{-0.82c-0.82c}{\frac{0.82c*(-0.82c)}{c^{2} }-1 }$

u'=0.9806c

Time for micrometeorite to pass spaceship can be calculated as:

$t'=\frac{length}{Relatie seed (u')}$

$t'=\frac{350}{0.9806c}$ (c = 3*10^8 m/s)

$t'=\frac{350}{0.9806* 3.0*10^{8} }$

$t'=1.1897*10^{-6} s$

t'=1.1897 μs

4 0

3 years ago

.<br><br> 1. True False<br> In AM waves, amplitude changes.

Dennis_Churaev [7]

That is true Step by step:

3 0

2 years ago

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A rocket ship carrying passengers blasts off to go from New York to Hong Kong, a distance of about 13,000 km. (a) How fast (in t

lapo4ka [179]

Answer:

0.14c

0.003 s

Explanation:

See attachment

8 0

3 years ago

a 3.18-kg rock is released from rest at a height of 26.6 m. ignore air resistance and determine (a) the kinetic energy at 26.6 m

antiseptic1488 [7]

Answer:

(a) 0 J

(b) 828.96 J

(c) 828.96 J

(d) 828.96 J

(e) 0 J

(f) 828.96 J

Explanation:

Given:

Mass of the rock is, $m=3.18\ kg$

Initial height of the rock is, $h_{i}=26.6\ m$

Final height of the rock is, $h_f=0\ m$

Initial velocity of the rock is, $v_i=0\ m/s(Rest)$

Acceleration due to gravity is, $g=9.8\ m/s^2$

(a)

Initial kinetic energy is given as:

$K_i=\frac{1}{2}mv_i^2$

Plug in the given values and solve for ' $K_i$ '. This gives,

$K_i=\frac{1}{2}\times 3.18\times 0^2=0$

Therefore, initial kinetic energy is 0 J.

(b)

Initial potential energy is given as:

$U_i=mgh_i\\U_i=3.18\times 9.8\times 26.6=828.96\ J$

Therefore, initial potential energy is 828.96 J.

(c)

Mechanical energy is equal to the sum of kinetic and potential energy. It is always a constant value. Therefore,

$ME=K_i+P_i\\ME=0+828.96=828.96\ J$

Therefore, mechanical energy at 26.6 m is 828.96 J.

(d)

Now, at the final height of 0 m, the decrease in potential energy will be equal to the increase in the kinetic energy. In other words, the potential energy at the start will be converted to kinetic energy at the bottom.

Therefore, kinetic energy at the 0 m is given as:

$K_f=U_i=828.96\ J$

(e)

Potential energy at the final height is given as:

$P_f=mgh_f=3.18\times 9.8\times 0=0\ J$

Therefore, final potential energy is 0 J.

(f)

Total mechanical energy is a constant and doesn't depend on the height.

So, total mechanical energy at 0 m is same as that at 26.6 m.

Total mechanical energy is 828.96 J.

8 0

3 years ago

Average velocity is different than average speed because calculating average velocity involves what?

Dominik [7]

Two things that aren't involved in speed: -- the straight-line distance between the start- and end- points. -- the direction from start-point to end-point.

8 0

3 years ago

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