Ask question

Ask question

All categories

Alexeev081 [22]

3 years ago

13

What are two deposit s made by water

1 answer:

Alexandra [31]3 years ago

3 0

Sinkholes and caves are 2 reasons. hope that helped

You might be interested in

A body weighing 108N moves with seed of 5ms–¹ in a horizontal circular path of radius 5m. Calculate the magnitude of the centrip

uysha [10]

Hi there!

Recall the equation for centripetal force;

$\boxed{F_c = \frac{mv^2}{r}}$

m = mass (kg)

v = velocity (m/s)

r = radius (m)

We are not given the mass directly, we are given the object's weight.

$W = mg$

$108 = 10m \\\\m = 10.8 kg$

Now, we can plug this value along with the given velocity and radius to solve:

$F_c = \frac{10.8(5^2)}{5} = \boxed{54N}$

8 0

3 years ago

Of orbital radius, orbital velocity, orbital circumference, or radial area swept through, which of these stays constant accordin

kow [346]

Answer:

dyow

Explanation:

sorrrey

5 0

3 years ago

The fastest time ever run at Pikes Peak is 7:57. That’s way too long. If we removed all the curves, making a straight line from

anygoal [31]

Answer: 271.4 s

Explanation:

We are told the top speed (maximum speed) $V_{max}$ the car has is:

$V_{max}=203 mph=90.74 m/s$ taking into account $1 mile=1609.34 m$

And the car's average acceleration $a_{ave}$ is:

$a_{ave}=0.091 g=2.93 ft/s^{2}=0.89 m/s^{2}$

Since:

$a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}$ (1)

Where:

$V_{f}=V_{max}=90.74 m/s$ is the car's final speed (top speed)

$V_{o}=0 m/s$ because it starts from rest

$\Delta t$ is the time it takes to reach the top speed

Finding this time:

$\Delta t=\frac{V_{f}-V_{o}}{a_{ave}}$ (2)

$\Delta t=\frac{90.74 m/s - 0 m/s}{0.89 m/s^{2}}$ (3)

$\Delta t=t_{1}=101.95 s$ (4)

Now we have to find the distance $d$ the car traveled at this maximum speed with the following equation:

$V_{f}^{2}=V_{o}^{2} + 2a_{ave} d$ (5)

Isolating $d$ :

$d=\frac{V_{f}^{2}}{2a_{ave}}$ (6)

$d=\frac{(90.74 m/s)^{2}}{2(0.89 m/s^{2})}$ (7)

$d=4625.70 m$ (8)

On the other hand, we know the total distance $D$ traveled by the car is:

$D=12.42 miles = 19988.052 m$

Hence the remaining distance is:

$d_{remain}=D-d=19988.052 m - 4625.70 m$ (9)

$d_{remain}=15362.35 m$ (10)

So, we can calculate the time $t_{2}$ it took to this car to travel this remaining distance $d_{remain}$ at its top speed $V_{max}$ , with the following equation:

$V_{max}=\frac{d_{remain}}{t_{2}}$ (11)

Isolating $t_{2}$ :

$t_{2}=\frac{d_{remain}}{V_{max}}$ (12)

$t_{2}=\frac{15362.35 m}{90.74 m/s}$ (13)

$t_{2}=169.45 s$ (14)

With this time $t_{2}$ and the value of $t_{1}$ calculated in (4) we can finally calculate the total time $t_{TOTAL}$ :

$t_{TOTAL}=t_{1}+ t_{2}$ (15)

$t_{TOTAL}=101.95 s + 169.45 s$ (16)

$t_{TOTAL}=271.4 s s$

5 0

4 years ago

When growing tomatoes with little sunlight, will using a mirror to reflect the sunlight give the same result as direct sunlight?

telo118 [61]

Answer:

No, it is not d true light

Explanation:

fruits generally plants need a direct sunlight

4 0

4 years ago

The 25-mph zone is 150 yards long. How much time did the student save (in seconds) by speeding past the school

VikaD [51]

Answer:

Time = 12.27seconds

Explanation:

Given

Speed = 25miles/hour

Distance = 150 yards = 150(0.000568182)miles

Distance (in miles) = 0.0852273miles

Get the time

Speed = Distance/Time

Time = Distance/Speed

Time = 0.0852273/25

Time = 0.0034hours

Time = 0.0034 * 3600secs

Time = 12.27seconds

7 0

3 years ago