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yan [13]
3 years ago
6

What is the molarity of a solution containing 8.0 moles of solute in a 569 ml of solution?

Chemistry
1 answer:
Ainat [17]3 years ago
4 0

Answer:

14.06 M

Explanation:

Molarity: moles of a solution / liters of a solution

We convert 569ml into liters for the equation by dividing milliliters by 1000.

569/1000 = 0.569L

Now that we have Liters we can do moles of a solution / liters of a solution:

8 / 0.569 = 14.06 M

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A, I believe it is 810liters of oxygen! Please correct me if im wrong
3 0
2 years ago
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Question 1
Lady bird [3.3K]

Answer:

Molecules vibrate in a fixed position.

Explanation:

first one is just wrong.

third is liquid

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4 0
2 years ago
The volume of oxygen, collected over water, is 185 mL at 25 degrees Celsius and 600 torr. calculate the dry volume of the oxygen
ivolga24 [154]

Answer:

0.1593 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.

P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.

<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>

4 0
3 years ago
4. How many grams of ammonium carbonate are needed to decompose in order to produce
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Answer:

14.23g of (NH4)2CO3

Explanation:

We'll begin by writing the balanced equation for the reaction.

(NH4)2CO3 –> (NH4)2O + CO2

Next,, we shall determine the mass of (NH4)2CO3 that decomposed and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of (NH4)2CO3 = 2[14+(4x1)] + 12 + (16x3)

= 2[14 +4] + 12 + 48

= 2[18] + 60 = 96g/mol

Mass of (NH4)2CO3 from the balanced equation = 1 x 96 = 96g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g.

Summary:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Finally, we can determine the mass of (NH4)2CO3 that decomposed to produce 6.52g of CO2 as follow:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Therefore, Xg of (NH4)2CO3 will decompose to produce 6.52g of CO2 i.e

Xg of (NH4)2CO3 = (96 x 6.52)/44

Xg of (NH4)2CO3 = 14.23g

Therefore, 14.23g of (NH4)2CO3 is needed to produce 6.52g of CO2.

4 0
3 years ago
HELP please! Which of these describes how heat is transferred by conduction
VLD [36.1K]
D. Air molecules touch the warm ground, heating them up
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