E = hf
E : photon energy
h : Plank's constant 6.63×10^-34
f : frequency
Hope it helped!
Answer:
a) θ = 14.23º, b) θ₂ = 75.77, c) t = 0.6019 s
Explanation:
This is a missile throwing exercise.
a) the reach of the ball is the distance traveled for the same departure height
R =
sin 2θ =
sin 2θ = 7.00 9.8 / 12.0²
2θ = sin⁻¹ (0.476389) = 28.45º
θ = 14.23º
the complementary angle that gives the same range is the angle after 45 that the same value is missing to reach 90º
θ ’= 90 -14.23
θ’= 75.77º
b) the two angles that give the same range are
θ₁ = 14.23
θ₂ = 75.77
the greater angle has a much greater height so the time of the movement is greater and has a greater chance of being intercepted by the other team.
C) the time of the pass can be calculated with the expression
x = v₀ₓ t
t = x / v₀ₓ
t = 7 / 11.63
t = 0.6019 s
I didn't have a dollar bill handy. So I conducted an extensive, exhaustive, in-depth, 2-minute internet search to determine the length of one. (I lived in Boston for 6 years and it had a profound effect on me. All during the 2 minutes of my research, I kept mumbling "dorla bill" to myself.) Anyway, the length of a US dorla bill is 6.14 inches.
We want to find out HOW MANY dorla bills it would take. We don't know that number yet, but we need to use it in our math, so we have to use something to put in its place until we find out the actual number. Most people would use 'x'. I'm going to use ' M '.
Length of 1 bill . . . . . 6.14 inches
Length of ' M ' bills . . . . . (6.14 M) inches
Circumference of the Earth at the equator . . . . . 40,075 km
inches in 1 foot . . . . . 12
feet in 1 meter . . . . . 3.28084
meters in 1 km . . . . . 1,000
This is all the outside information we need. The rest is all arithmetic.
==========================================
length of 1 bill, in inches . . . . . 6.14 inches
length of ' M ' bills, in inches . . . . . (6.14 M inches)
length of ' M ' bills, in feet . . . . .(6.14 M inches) x (1 foot/12 inches)
length of ' M ' bills, in meters . . . . .
(6.14 M inches) x (1 foot/12 inches) x (1 meter/3.28084 foots)
length of ' M ' bills, in km . . . . . (6.14 M inches) x(1 foot/12 inches) x(1 meter/3.28084 foots) x(1 km/1,000 m)
. . . . . . . . . . ^ these numbers are equal \/ . . . . . . . . . .
Circumference of the equator . . . . . 40,075 km
==============================================
Gather all the numbers together, and all the units together:
(6.14M x 1 x 1 x 1)/(12 x 3.28084 x 1,000) x (inch-foot-meter-km/inch-foot-meter) = 40,075 km
Do the arithmetic, and cancel out units that appear on both top and bottom:
(0.000155956 M) x (km) = 40,075 km
Divide each side by 0.000155956 km, and you'll have:
M = (40,075 / 0.000155956)
M = 256.96 million bills
============================================
Quick check, just to see if it makes sense:
Round each dorla bill to 6 inches even:
(256.96 million x 6 inches) x (1 ft/12 inch) x (1 mile/5280 ft) = 24,333 miles
Well, the same internet says the equator's circumference is 24,901 miles. YAY ! ! ! As an engineer, I'd say the two numbers match perfectly. So the answer to the question is confirmed to be
256.96 million bills
(2.57 x 10⁸ bills)
The first law of thermodynamics is similar to the conservation of energy because both state that this element (i.e., energy) is not created/destroyed in the universe.
<h3>What is the first law of thermodynamics?</h3>
The first law of thermodynamics is a popular law in physics that states change in internal energy is equal to the energy added and the work made by a closed system.
Moreover, the law of conservation of energy states that it cannot be created/destroyed in the Universe, which is deeply associated with principles of thermodynamics.
In conclusion, the first law of thermodynamics is similar to the conservation of energy because both state that this element (i.e., energy) is not created/destroyed in the universe.
Learn more about the first law of thermodynamics here:
brainly.com/question/1613201
#SPJ1
Answer:
Explanation:
Speed given = 125 m /min
125 /60 m /s
In 450 second it will travel
= 450 x 125 / 60
=937.5 m.
As the distance is covered in less than 450 seconds , The distance must be less than 937.5 m
In 400 seconds , it will travel
= 400 x 125 / 60
833.33 m
Since the distance is covered in more than 400 seconds , the distance must be more than ie 833.33 .
Hence the distance covered is more than .833 m but less than 937.5
In either case these distance are more than .8 km .