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3 years ago

Please help! Pleaseeee

Mathematics

2 answers:

murzikaleks [220]3 years ago

7 0

No solution (top equation is multiplied by -4 all values would cancel out)

Mumz [18]3 years ago

5 0

(1/2)x +y = 3 (equation 1)
2x +4y = 12 (equation 2)

((1/2)x +y = 3) x4
= 2x +4y = 12

2x +4y = 12
-
2x +4y = 12
= nothing

answer is B infinitely many solutions as the lines are stacked on top of another.

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The answers on how I do these problems the correct way

dimulka [17.4K]

Step-by-step explanation:

so what you need to do is answer the questions with () and then do the other part

8 0

4 years ago

Which inequality comparing two of the expressions below is true when 0.5

Aleonysh [2.5K]

Answer:

Option C

Step-by-step explanation:

Given 0.5≤ x ≤ 0.7

According to the range of x, we will check which option is true

Let x = 0.6

A. $\frac{x}{3} > \sqrt{x}$

If x = 0.6

∴0.6/3 > √0.6 ⇒ 0.2 > 0.77 ⇒ Wrong inequality

B. x³ > 1/x

If x = 0.6

∴ 0.6³ > 1/0.6 ⇒ 0.216 > 1.667 ⇒ Wrong inequality

C. √x > x³

If x = 0.6

∴ √0.6 > 0.6³ ⇒ 0.77 > 0.216 ⇒ True inequality

D. (x/3) > (1/x)

If x = 0.6

∴ 0.6/3 > 1/0.6 ⇒ 0.2 > 1.667 ⇒ Wrong inequality

So, The true inequality is option C

8 0

3 years ago

Find two consecutive positive even integers such that the square of the first decreased by 64 equals 3 times the second.

IRINA_888 [86]

Answer:

10 and 12

Step-by-step explanation:

let the consecutive even integers be n and n + 2 , then

n² - 64 = 3(n + 2) ← distribute parenthesis

n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )

n² - 3n - 70 = 0 ← in standard form

(n - 10)(n + 7) = 0 ← in factored form

Equate each factor to zero and solve for n

n - 10 = 0 ⇒ n = 10

n + 7 = 0 ⇒ n = - 7

Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12

The 2 numbers are 10 and 12

8 0

3 years ago

Write the equation of the circle that has a center of (-7, 17) with a radius of V19.

kipiarov [429]

I think your question seems to be :-

Write the equation of the circle that has a center of (-7, 17) with a radius of √19

So , as we know that the equation of circle with centre at (h,k) and radius r is given by ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ . Now , using same concept in this question ;

${:\implies \quad \sf \{x-(-7)\}^{2}+(y-17)^{2}=(\sqrt{19})^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{(x+7)^{2}+(y-17)^{2}=19}}}$

This is the required equation of Circle 

8 0

2 years ago

Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y

Travka [436]

( y - 4 ) ( y² + 4 y + 16 ) =
= y³ + 4 y² + 16 y - 4 y² - 16 y - 64 = y³ - 64
If the result is the polynomial of the form:
y³ + 4 y² + a y - 4 y² - a y - 64
a = 16

8 0

3 years ago