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lianna [129]
2 years ago
12

The radiation detector that uses detection of flashes of light is a _____

Physics
1 answer:
Maslowich2 years ago
3 0

The radiation detector that uses detection of flashes of light is a <u>scintillation counter.</u>

<h3>What is a scintillation counter?</h3>

A scintillation counter detects and measures ionizing radiation by using the excitation action of incoming radiation on a scintillating substance and detecting the light pulses that arise.

One of the most critical considerations for anyone who operate with or near radiation is being aware of the amounts of radiation present.

This is generally performed through the use of several types of radiation detectors.

The radiation detector that uses detection of flashes of light is a scintillation counter.

Hence,scintillation counter is the correct answer.

To learn more about the scintillation counter, refer:

brainly.com/question/12763694

#SPJ4





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Answer:D

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A critical period begins and ends abruptly
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yes

Explanation:

<em>A critical period? </em>

<em>A.begins and ends abruptly </em>

<em>B.begins and ends gradually </em>

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Which best defines nitrogen fixation? the process of creating free nitrogen for plants to absorb the breakdown of nitrogen in th
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The nitrogen fixation is the process of conversion of nitrogen gas into a usable form.

Answer: Option 3

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A surgeon makes an incision that divides the patient's abdomen into superior
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Hope this helps

3 0
3 years ago
In this circuit (see picture), which resistor will draw the least power?
Basile [38]
A few different ways to do this: 

Way #1: 
The current in the series loop is  (12 V) / (total resistance) . 
(Turns out to be 2 Amperes, but the question isn't asking for that.)

In a series loop, the current is the same at every point, so it's
the same current through each resistor.

The power dissipated by a resistor is  (current)² · (resistance),
and the current is the same everywhere in the circuit, so the
smallest resistance will dissipate the least power.  That's  R1 .

And by the way, it's not "drawing" the most power.  It's dissipating it.

Way #2:
Another expression for the power dissipated by a resistance is

                 (voltage across the resistance)²  /  (resistance)  .

In a series loop, the voltage across each resistor is

          [ (individual resistance) / (total resistance ] x battery voltage.

So the power dissipated by each resistor is

         (individual resistance)² x [(battery voltage) / (total resistance)²]

This expression is smallest for the smallest individual resistance.
(The other two quantities are the same for each individual resistor.)
So again, the least power is dissipated by the smallest individual resistance.
That's R1 .                                      

Way #3:  (Einstein's way)
If we sat back and relaxed for a minute, stared at the ceiling, let our minds
wander, puffed gently on our pipe, and just daydreamed about this question
for a minute or two, we might have easily guessed at the answer.

===>  When you wire up a battery and a light bulb in series, the part
that dissipates power, and gets so hot that it radiates heat and light, is
the light bulb (some resistance), not the wire (very small resistance).
3 0
3 years ago
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