Ask question

Ask question

All categories

chubhunter [2.5K]

3 years ago

5

what magnetic field is needed to exert a force of 0.4N on a 0.1m long conductor if it carries a current of 2A perpendicular to t

he magnetic field?

1 answer:

serious [3.7K]3 years ago

6 0

Answer:

2T

Explanation:

Use F = BIL

F = 0.4N

B = ??

I = 2A

L = 0.1m

You might be interested in

Describe one common critique or criticism of Utilitarianism. To what extent do you agree or disagree with this criticism?

lisabon 2012 [21]

The second most common criticism of utilitarianism is that it is impossible to apply - that happiness (etc) cannot be quantified or measured, that there is no way of calculating a trade-off between intensity and extent, or intensity and probability (etc), or comparing happiness to suffering.

7 0

2 years ago

What is the net force required to accelerate a 16 kg box at a rate or 1.4 m/s^2

stich3 [128]

You can use Newton's Second Law which states:
$\sum \vec{F} = m\vec{a}$

Plug in given information:
$\sum \vec{F}=16(1.4) = 22.4N$

This is closest to option b which is your answer.

8 0

3 years ago

Two forces, F? 1 and F? 2, act at a point, as shown in the picture. (Figure 1) F? 1 has a magnitude of 9.20 N and is directed at

Stolb23 [73]

Answer:

a. Fx = -8.089 N b. Fy = 3.525 N c. 8.824 N d. 336.45°

Explanation:

Since F₁ = 9.2 N and acts at 57° above the negative axis in the second quadrant, its x-component is -F₁cos57° and its y- component is F₁sin57°

Since F₁ = 5.2 N and acts at 53.7° below the negative axis in the third quadrant, its x-component is -F₂cos53.7° and its y- component is -F₂sin53.7°

Part A

What is the x component Fx of the resultant force?

The x component of the resultant force Fx = -F₁cos57° + -F₂cos53.7° = -9.2cos57° + (-5.2cos53.7°) = (-5.011 - 3.078) N = -8.089 N

Part B

What is the y component Fy of the resultant force?

The y component Fy of the resultant force = F₁sin57° + -(F₂sin53.7°) = 9.2sin57° - 5.2sin53.7° = (7.716 - 4.191) N = 3.525 N

Part C

What is the magnitude F of the resultant force?

The magnitude F of the resultant force = √(Fx² + Fy²)

F = √(-8.089² N + 3.525² N) = √65.432 + 12.426 = √77.858 = 8.824 N

Part D

What is the angle ? that the resultant force forms with the negative x axis?

The angle the resultant force makes with the negative x axis is given by

θ = tan⁻¹(Fy/Fx) = tan⁻¹(3.525/-8.089) = tan⁻¹-0.4358 = -23.55°.

To measure it from the negative x axis, we add 360. So, our angle = 360 -23.55 = 336.45°

7 0

3 years ago

Ivan drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Ivan drove h

lesya692 [45]

Answer:252 miles

Explanation:

Given

During his way to mountain it took 7 hr to drive

and during his return trip it took 4 hr to return

Let x be the distance between home and mountain

average speed for return is 27 miles per hour faster than his former trip

let v be the speed on his way to mountain thus v+27 is his return speed

thus $7=\frac{x}{v}$ ----1

for return trip

$4=\frac{x}{v+27}$ -----2

divide 1 & 2

$\frac{7}{4}=\frac{x\cdot (v+27)}{v\cdot x}$

$7v=4v+4\cdot 27$

$3v=4\cdot 27$

$v=36 mph$

thus $x=7\times 36=252\ miles$

7 0

3 years ago

7. How do Newton’s laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players can pass a

Arisa [49]

The first law states that “objects at rest and objects in motion remain in motion in a straight line unless acted upon by an unbalanced force”. Keeping the ice smooth will make sure there is not friction, friction would slow the puck down

5 0

3 years ago

Read 2 more answers