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chubhunter [2.5K]

2 years ago

5

what magnetic field is needed to exert a force of 0.4N on a 0.1m long conductor if it carries a current of 2A perpendicular to t

he magnetic field?

1 answer:

serious [3.7K]2 years ago

6 0

Answer:

2T

Explanation:

Use F = BIL

F = 0.4N

B = ??

I = 2A

L = 0.1m

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2 years ago

What is the relationship between matter and energy as it changes states of matter (phase changes?)

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3 years ago

Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven

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3 years ago

.(क) निम्न में से किस मीटर का प्रतिरोध उच्चतम होता है:

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eshehusok

4 0

2 years ago

A very delicate sample is placed 0.150 cm from the objective lens of a microscope. The focal length of the objective is 0.140 cm

iVinArrow [24]

Answer:

m = 14*26 = 364

Explanation:

overall magnification is given as m

$m = m_{o}* m_{e}$

mo magnification of objective lens

me magnification of EYE lens

where mo is given as

$m_{o} = \frac{v_{o}}{-u _{0}}$

and me as

$m_{e} = 1+\frac{D}{f_{e}}$

d is distant of distinct vision = 25.0 cm for normal eye

fe = focal length of eye piece

focal length of objective lense is 0.140 cm

we know that

$\frac{1}{v_{0}}-\frac{1}{u_{0}}=\frac{1}{f_{0}}$

$\frac{1}{v_{0}} = \frac{1}{u_{0}} + \frac{1}{f_{0}}$

$\frac{1}{v_{0}} = \frac{1}{0.150} + \frac{1}{0.14}$

$\frac{1}{v_{o}} = 2.1 cm$

$m_{o} = \frac{2.1}{0.150} = 14$

$m_{e} = 1+\frac{25}{1}$

$m_{e} =26$

$m = m_{o}* m_{e}$

m = 14*26 = 364

4 0

3 years ago