1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inessss [21]
3 years ago
7

a bottle of rubbing alcohol is labeled 70%(v/v) how many milliliters of isopropyl alcohol are in a 400ml bottle of this solution

?
Chemistry
1 answer:
xz_007 [3.2K]3 years ago
3 0
 The number of   milliliters  of  isopropyl alcohol that are  in   a 400 ml bottle  of this solution  is 280 Ml

   calculation

  % V/V =  volume of  solute/ volume  of  solution  x 100
 Let the volume  of solute  be =  y  ml
 the volume  of  solution =  400 ml
convert 70%  to fraction = 70/100

 by  substituting  the value  in the equation 

 = y  ml/  400 ml =  70/100

by cross  multiplication

100y =400 x70
100y=  28000
y= 280 ml
You might be interested in
What conclusion can be draw about the heat of fusion of water from the heating curve? A) The potential energy of fusion represen
zysi [14]
The answer would be c.

6 0
3 years ago
Read 2 more answers
A 151.5-g sample of a metal at 75.0°C is added to 151.5 g at 15.1°C. The temperature of the water rises to 18.7°C. Calculate the
Kryger [21]

Answer:

The specific heat capacity of the metal is 0.268 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 151.5 grams

The temperature of the metal = 75.0 °C

Temperature of water = 15.1 °C

The temperature of the water rises to 18.7°C.

The specific heat capacity of water is 4.18 J/°C*g

Step 2: Calculate the specific heat capacity of the metal

heat lost = heat gained

Q = m*c*ΔT

Qmetal = - Qwater

m(metal) * c(metal) * ΔT(metal) = m(water) * c(water) * ΔT(water)

⇒ mass of the metal = 151.5 grams

⇒ c(metal) = TO BE DETERMINED

⇒ΔT( metal) = T2 - T1 = 18.7 °C - 75.0 °C = -56.3 °C

⇒ mass of the water = 151.5 grams

⇒ c(water) = 4.184 J/g°C

⇒ ΔT(water) = 18.7° - 15.1 = 3.6 °C

151.5g * c(metal) * -56.3°C = 151.5g * 4.184 J/g°C * 3.6 °C

c(metal) = 0.268 J/g°C

The specific heat capacity of the metal is 0.268 J/g°C

5 0
3 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
Dinitrogen pentoxide is used in the preparation of explosives. If 7.93 mol of
Tpy6a [65]

The volume of O₂ produced: 84.6 L

<h3>Further explanation</h3>

Given

7.93 mol of  dinitrogen pentoxide

T = 48 + 273 = 321 K

P = 125 kPa = 1,23365 atm

Required

Volume of O₂

Solution

Decomposition reaction of dinitrogen pentoxide

2N₂O₅(g)→4NO₂(g)+O₂ (g)

From the equation, mol ratio N₂O₅ : O₂ = 2 : 1, so mol O₂ :

= 0.5 x mol N₂O₅

= 0.5 x 7.93

= 3.965 moles

The volume of O₂ :

\tt V=\dfrac{nRT}{P}\\\\V=\dfrac{3.965\times 0.082\times 321}{1.23365}\\\\V=84.6~L

5 0
3 years ago
Over-encouraging lesser skilled players can lead to embarrassment.<br> a. True<br> b. False
Margarita [4]
My answer would be a. True
6 0
3 years ago
Read 2 more answers
Other questions:
  • Anyone know what the answer is??
    7·1 answer
  • In addition, they are poor conductors of
    10·1 answer
  • The specific heat of gold is 0.031 calories/gram°C. If 10.0 grams of gold were heated and the temperature of the sample changed
    15·2 answers
  • What mineral is not a structural component of bone?
    13·1 answer
  • A) What is the maximum number of grams of nickel bromide that can be produced from the reaction of 67.8 g of nickel with 37.3 g
    10·1 answer
  • List at least two chemical reactions that resulted in the yellow orange or red preList at least two chemical reactions that resu
    12·1 answer
  • PLEASE HELP ASAP!!!!!!!!
    13·1 answer
  • Help asap!!
    12·1 answer
  • An energy bill indicates that the customer used 1024 kWh in July. How many joules did the customer use?
    7·1 answer
  • Coal power and nuclear power are
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!