a bottle of rubbing alcohol is labeled 70%(v/v) how many milliliters of isopropyl alcohol are in a 400ml bottle of this solution
1 answer:
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Answer:
Partial pressure of in the gas was 733 torr and mass of
in the sample was 2.12 g.
Explanation:
a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of )
Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.
So, partial pressure of = (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr
b) Lets assume that behaves ideally. Hence-
PV=nRT
where P is pressure of , V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin
here P = 733 torr = = 0.9646 atm
V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K
So,
=
= 0.0259 moles
As 3 moles of are produced from 2 moles of
therefore 0.0259 moles of
are produced from
moles or 0.0173 moles of
.
Molar mass of = 122.55 g
So mass of in sample =
= 2.12 g
The electric potential due to ammonia at a point away along the axis of a dipole is 1.44 10^-5 V.
<u>Explanation:</u>
Given that 1 D = 1 debye unit = 3.34 × 10-30 C-m.
Given p = 1.47 D = 1.47 3.34
10^-30 = 4.90
10^-30.
V = 1 / (4π∈о) (p cos(θ)) / (r^2)
where p is a permanent electric dipole,
∈ο is permittivity,
r is the radius from the axis of a dipole,
V is the electric potential.
V = 1 / (4 3.14
8.85
10^-12)
(4.90
10^-30
1) / (55.3
10^-9)^2
V = 1.44 10^-5 V.