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shepuryov [24]
2 years ago
12

What is the gpe of the ball at position a (20-m high)

Physics
1 answer:
Lesechka [4]2 years ago
5 0

Answer:

Explanation:

P.E. = mgh = 7.7 * 9.81 * 20   j

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A 9-volt battery is used to power two lightbulbs in a series circuit. The first light bulb has a
butalik [34]

Explanation:

Total Resistance: 3+2 = 5 ohms

V=9V

Power = V²/R

=9²/5

=81/5

=16.2 W

6 0
2 years ago
How much WATER needed to offset the force of jumping down from 20metre in vacuum environment,to keep me alive.
kenny6666 [7]

Answer:

it's quite difficult

Explanation:

6 0
2 years ago
How could we expect a white paper to appear when viewed in a red light?
Xelga [282]
The accurate answer is:
You could expect a white paper to have a red tone when viewed in a red light. This is the case because of the neutrality of the white paper.
4 0
3 years ago
(a) A long, straight solenoid has N turns, uniform cross-sectional area A, and length l. Show that the inductance of this soleno
Paul [167]

Answer:

a. L = μ₀AN²/l b. 1.11 × 10⁻⁷ H

Explanation:

a. The magnetic flux through the solenoid, Ф = NAB where N = number of turns of solenoid, A = cross-sectional area of solenoid and B = magnetic field at center of solenoid = μ₀ni where μ₀ = permeability of free space, n = number of turns per unit length = N/l where l = length of solenoid and i = current in solenoid.

Also, Li = Ф where L = inductance of solenoid.

So, Li = NAB

= NA(μ₀ni)

= NA(μ₀Ni/l)

Li = μ₀AN²i/l

dividing both sides by i, we have

So, L = μ₀AN²/l

b. The self- inductance, L = μ₀AN²/l where

A = πd²/4 where d = diameter of solenoid = 0.150 cm = 1.5 × 10⁻³ m, N = 50 turns, μ₀ = 4π × 10⁻⁷ H/m and l = 5.00 cm = 5 × 10⁻² m

So, L = μ₀AN²/l

L = μ₀πd²N²/4l

L = 4π × 10⁻⁷ H/m × π(1.5 × 10⁻³ m)²(50)²/(4 × 5 × 10⁻² m)

L = 11,103.3 × 10⁻¹¹ H

L = 1.11033 × 10⁻⁷ H

L ≅ 1.11 × 10⁻⁷ H

6 0
3 years ago
If
timama [110]

Answer:

Workdone = 1960 Joules.

Explanation:

Given the following data;

Mass = 5kg

Force = 49N

Height (distance) = 40m

To find the workdone;

Workdone = force * distance

Substituting into the equation, we have;

Workdone = 49*40

Workdone = 1960 Joules.

Therefore, the amount of work done on the bowling ball to lift it is 1960 Joules.

7 0
3 years ago
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