Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J
Look at it this way:
Every time the plane flies through 400 miles of air,
the air moves it 40 miles backwards.
So it only covers 360 miles of ground in an hour.
Are there any options or is it not multiple choice.
Four electrons are placed at the corner of a square
So we will first find the electrostatic potential at the center of the square
So here it is given as

here
r = distance of corner of the square from it center



now the net potential is given as


now potential energy of alpha particle at this position

Now at the mid point of one of the side
Electrostatic potential is given as

here we know that



now potential is given as


now final potential energy is given as

Now work done in this process is given as


