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3 years ago

Which of these celestial objects is the smallest

Chemistry

2 answers:

Verizon [17]3 years ago

7 0

Answer:

Explanation:

I looked it up lol.

RideAnS [48]3 years ago

6 0

Answer: Dwarf planet are the smallest celestial bodies

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Anastaziya [24]

Answer/Explanation: A weight lifted vertically to acquire gravitational potential energy. A weight lifted vertically to acquire gravitational potential energy. If the force were to be removed, the object would fall back down to the ground and the gravitational potential energy would be transferred to kinetic energy of the falling object.

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3 years ago

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Find the speed of a mouse that runs 33 feet in 3 seconds.

NeTakaya

The speed of the mouse is 11 ft/s

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3 years ago

Gather data: On the CONTROLS pane, set the Reactant concentration to 2.0 mol/L, the Surface area to Maximum, and the Temperature

Vikentia [17]

Answer:

Explanation:

We can use the Arrhenius equation to relate the activation energy and the rate constant, k, of a given reaction:

k=Ae−Ea/RT

In this equation, R is the ideal gas constant, which has a value 8.314 J/mol/K, T is temperature on the Kelvin scale, Ea is the activation energy in joules per mole, e is the constant 2.7183, and A is a constant called the frequency factor, which is related to the frequency of collisions and the orientation of the reacting molecules.

Both postulates of the collision theory of reaction rates are accommodated in the Arrhenius equation. The frequency factor A is related to the rate at which collisions having the correct orientation occur. The exponential term,

e−Ea/RT, is related to the fraction of collisions providing adequate energy to overcome the activation barrier of the reaction.

6 0

3 years ago

An experimenter places a piece of solid metal weighing 255g into a graduated cylinder which she then fills with mercury. After w

damaskus [11]

Answer: the density of the solid metal is 22.5176 g/cm

Explanation:

Given that;

mass of solid metal = 255 g

the cylinder and its contents weigh 101g less than before

also given that density of mercury = 13.6 g/cm³

Volume of the solid metal = volume of mercury which was absent in the first weighing

so let volume = Vcm³

Mass of mercury which was absent in the first weighing = density × volume

= 13.6 g/cm³ × Vcm³ = 13.6V g

now since the cylinder and its contents weigh 101g less than before,

it means the difference in mass between the solid and metal and the mass of mercury is equal to 101 g

255 - 13.6V g = 101g

13.6V g = 255 g - 101 g

13.6V = 154

V = 154 / 13.6

V = 11.3245 cm³

Now Density of solid metal will be;

⇒ mass / volume

= 255 / 11.3245

= 22.5176 g/cm

Therefore, the density of the solid metal is 22.5176 g/cm

7 0

3 years ago

Consider a general reaction A ( aq ) enzyme ⇌ B ( aq ) The Δ G ° ′ of the reaction is − 9.130 kJ ⋅ mol − 1 . Calculate the equil

Liula [17]

Answer:

K = 39.85

ΔG= -6.9 kJ/mol

Explanation:

Step 1: Data given

The ΔG°′ of the reaction is − 9.130 kJ/mol

Temperature = 25.0 °C = 298 K

Body temperature = 37.0 °C = 310K

the concentration of A is 1.9 M

the concentration of B is 0.80 M

Step 2: The reaction

A (aq) ⇌ B (aq)

Step 3:

ΔG° = -RT ln K

⇒with ΔG° = standard Gibbs free energy change = − 9.130 kJ/mol

⇒with R = the gas constant = 8.314 J/mol*K

⇒with T = the temperature = 298 K

⇒with K = the equilibrium constant = TO BE DETERMINED

− 9130 J/mol = - 8.314 * 298 * ln K

ln K = 3.685

K = e^3.685

K = 39.85

Step 4: The reaction at body temperature

ΔG= ΔG° + RT ln [B]/[A]

⇒with ΔG° = Gibbs free energy change

⇒with ΔG° = standard Gibbs free energy change = − 9130 J/mol

⇒with R = the gas constant = 8.314 J/mol*K

⇒with T = the temperature = 310 K

⇒with [A] = 1.9 M

⇒with [B] = 0.80 M

ΔG= -9130 J/mol + 8.314 J/mol*K * 310 K * ln (1.9/0.80)

ΔG= -9130 J/mol + 2229.4J/mol

ΔG=-6900.6 J/mol = -6.9 kJ/mol

6 0

3 years ago