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Deffense [45]
3 years ago
7

The gas inside a balloon exerts a pressure of 3atm at 298 K. What is the temperature required to increase the pressure to 6 atm?

Chemistry
1 answer:
podryga [215]3 years ago
7 0

Answer: 596 atm

Explanation:

Given that,

Original pressure of balloon P1 = 3atm

Original temperature of balloon T1 = 298K

New pressure of balloon P2 = 6atm

New temperature of balloon T2 = ?

Since pressure and temperature are given while volume is constant, apply the formula for Pressure law

P1/T1 = P2/T2

3 atm / 298K = 6 atm / T2

To get the value of T2, cross multiply

3 atm x T2 = 6 atm x 298K

3 atmT2 = 1788 atmK

Divide both sides by 3 atm

3 atmT2 / 3 atm = 1788 atmK / 3 atm

T2 = 596 atm

Thus, a temperature of 596 atmospheres is required to increase the pressure to 6 atm.

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Explanation:

Upon dissolution of KCl heat is generated and temperature of the solution raises.

Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.

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Mass of solution will be the sum of mass of water and mass of KCl.

       Mass of Solution = mass of water + (no. of moles of KCl × molar mass)

                                    = 200 g + (0.25 mol \times 54.5 g/mol)

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Relation between heat, mass and change in temperature is as follows.

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Therefore, putting the given values into the above formula as follows.

                     Q = mC \Delta T

            4310 J = 213.625 g \times 4.184 J/g^{o}C \times \Delta T      

              \Delta T = 4.82^{o}C

Thus, we can conclude that rise in temperature will be 4.82^{o}C.

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