Answer: 596 atm
Explanation:
Given that,
Original pressure of balloon P1 = 3atm
Original temperature of balloon T1 = 298K
New pressure of balloon P2 = 6atm
New temperature of balloon T2 = ?
Since pressure and temperature are given while volume is constant, apply the formula for Pressure law
P1/T1 = P2/T2
3 atm / 298K = 6 atm / T2
To get the value of T2, cross multiply
3 atm x T2 = 6 atm x 298K
3 atmT2 = 1788 atmK
Divide both sides by 3 atm
3 atmT2 / 3 atm = 1788 atmK / 3 atm
T2 = 596 atm
Thus, a temperature of 596 atmospheres is required to increase the pressure to 6 atm.
