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Pavel [41]
3 years ago
7

An automobile engine provides 642 Joules of work to push the pistons. In this process the internal energy changes by -2952 Joule

s. Calculate q for the engine. This represents the amount of heat that must be carried away by the cooling system.Calculate the change in the internal energy of the engine.
Chemistry
1 answer:
faust18 [17]3 years ago
4 0

Answer:

Recall from the 1st law of thermodynamic -  Energy Balance gives;

assuming : there is no change in kinetic and potential energy, a steady state process, etc.

ΔU = ΔQ + ΔW

For this system, ΔW = +ve (engine does the work)

ΔU = -2952J

ΔQ = -ve? (Heat energy is been released)

Since the heat energy is removed,  the internal energy must increase by

-2952J = 642J - ΔQ

ΔQ = (642 + 2952) = 3594 J was released from the engine and the amount that must be cooled off

Now to find the change in the internal energy of the engine?

Note that as as soon as the heat is removed, there would not be any change in the internal energy of the system because all the energy from the burning of the measure of fuel has been removed.

so ΔU = 0J

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. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the
Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

\frac{P}{T}=k

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

\frac{P1}{T1} =\frac{P2}{T2}

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

  • P1= 0.450 atm
  • T1= 20 C= 293.15 K (being 0 C= 273.15 K)
  • P2=0.750 atm
  • T2= ?

Replacing:

\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}

Solving:

T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }

T2=\frac{0.750 atm}{0.450 atm} *293.15K

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0
3 years ago
Substances that are good conductors of heat and electricity at room temperature usually
Gnom [1K]

Answer:

the answer is electric

Explanation:

i think so

7 0
3 years ago
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid at 0°C?
Marrrta [24]
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<span>
Energy = 5 grams x 334 J/g
</span><span>Energy = 1670 J</span>
4 0
3 years ago
A truck is moving at the rate of 40 km/hr. How far does it move when it stops after 5 seconds?
seraphim [82]
First of all, this is the chemistry section, while your question is a physics question. Anyway I'll tell you how to solve it.

First we need to find the rate that the truck moves in a second.

1km = 1000m
40km = 40000m
40000m/hr
1 hour = 60 minutes
40000m/hr ÷ 60 = 666.66(repeating)/minute
1 minute = 60 seconds
666.66m/min ÷ 60 = 11.11(rep)m/s

Next we simply multiply the speed of the truck by the number of seconds it travels.

11.11 × 5 = 55.55
Make sure to round it unless you indicate the repeating decimal.
The truck moved 55.56m in 5 seconds.
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How do you balance hgo ?
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