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babunello [35]
3 years ago
12

PLEASE HELP ME!!!!!!!!!!!

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer: to find f(-4)

umka21 [38]3 years ago
4 0

Answer:

The answer is -4

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What is 7/12 in simplest form?
ikadub [295]
If it stays as fraction the answer would be 7/14
8 0
3 years ago
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Please help thanks in advance!!!!!
dedylja [7]

Answer:

5

Step-by-step explanation:

so 1/5 of 10 is 5 and 1/5 5 would be 1

area is LxW

so 5x1=5

6 0
3 years ago
When as rate, 100 miles in 5 hours would be ????? miles per hour
koban [17]

Answer:

20

Step-by-step explanation:

5 divided by 100 = 20

3 0
3 years ago
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8x=-4(x+3)<br> I would really appreciate some help
olganol [36]

Answer:

x = -1

Step-by-step explanation:

8x = - 4(x + 3)

8x = -4x - 12

+4x  +4x

<u>12x = -12</u>

12       12

x = -1

  • Remember, a negative times a positive equals a negative
  • Remember, a negative divided by a positive equals a negative

Hope this helps you!!! :)

4 0
3 years ago
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Select the correct answer for each statement. (k+2, k+3 , k+4) or (k+10, k+12, k+14) will yield consecutive odd integers. (k+6,
almond37 [142]

Answer:

Step-by-step explanation:

one

The only really certain way of getting an odd integer is to do 2k + 1. Therefore the answer should be something like 2k+1, 2k+3, 2k + 5

The best I can do for the first one is to assume that k is odd and that the answer is k + 10, k+12, k+14, but I would ask your instructor if this is merely the best answer out of a poor lot or if the question really has no answer.

Two things should be noted.

1. k has to be odd.

2. The first choice has to give consecutive integers because what is added on is 2 3 and 4. Those numbers are consecutive.

Two

k+1, k+2, k+3. See point 2 above. k is a constant and any number. 1,2,3 are consecutive so the results are consecutive. Even if k < 0 the numbers will be consecutive.

k= - 10

k+1 = - 9

k+2 = -8

k+3 = - 7

These are consecutive.

Your first choice will give either consecutive odd or even numbers depending on what k is.

If k = even, then k+6, k+ 8, k+10 will all be even.

If k = odd then the givens will be odd.

4 0
3 years ago
Read 2 more answers
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