Answer:
D. x≥ 9
Step-by-step explanation:
√x-9 should be ≥ 0
so, x-9≥0
=> x ≥ 9
<em>Answer:</em>
<em>56a</em>
<em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>8(3 + 4) = </em>
<em>= 8×3 + 8×4</em>
<em>= 24 + 32</em>
<em>= 56</em>
<em>Good luck !</em>
Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3
(r, theta)= (8, 3/2 pi)
r=(x^2 +y^2)^(1/2)
theta= 3/2 pi
x= r(costheta)
y=r(sintheta)
x=8(cos(3/2 pi))
y=8(sin(3/2 pi))
x=8(0)
y=8(-1)
x=0
y=-8
r=((-8)^2+(0)^2)^(1/2)
r=(64+0)^(1/2)
r=8
rectangular coordinates= (0,-8)
