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dangina [55]
3 years ago
13

Complete the equation for the dissociation of CdCl 2 ( aq ) . CdCl2(aq). Omit water from the equation because it is understood t

o be present. equation: CdCl 2 ( aq ) ⟶
Chemistry
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

The answer to your question is         CdCl₂  ⇒   Cd⁺²  +  2Cl⁻¹      

Explanation:

Data

Reactant = CdCl₂ (aq)

Process

1.- Determine the products of this reaction

The products will be the elements that form part of this compound (Cadmium and chlorine).

2.- Write the dissociation reaction

                      CdCl₂  ⇒   Cd⁺²  +  Cl⁻¹

3.- Balance the reaction

                      CdCl₂  ⇒   Cd⁺²  +  Cl⁻¹      

            Reactants    Elements     Products

                    1                 Cd                 1

                    2                 Cl                  1

The reaction is unbalanced

                     CdCl₂  ⇒   Cd⁺²  +  2Cl⁻¹      

            Reactants    Elements     Products

                    1                 Cd                 1

                    2                 Cl                  2

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Answer:

V = 177.4 L.

Explanation:

Hello there!

In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

PV=nRT\\\\PV=\frac{m}{MM}RT

Thus, by solving for volume we obtain:

V=\frac{mRT}{MM*P}

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

V=\frac{87.8g*0.08206\frac{atm*L}{mol*K}*537K}{54g/mol*0.404atm}\\\\V=177.4L

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6 0
3 years ago
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Pepsi [2]
<em>Q=mcΔT</em>
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5 0
3 years ago
A process stream contains 450 mol/s benzene and 375 mol/s toluene. Calculate the mole fraction of benzene in the process stream.
Tema [17]

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Explanation:

4 0
3 years ago
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boyakko [2]

Answer:

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Explanation:

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4 0
3 years ago
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