Answer:
Rate of reaction = -d[D] / 2dt = -d[E]/ 3dt = -d[F]/dt = d[G]/2dt = d[H]/dt
The concentration of H is increasing, half as fast as D decreases: 0.05 mol L–1.s–1
E decreseas 3/2 as fast as G increases = 0.30 M/s
Explanation:
Rate of reaction = -d[D] / 2dt = -d[E]/ 3dt = -d[F]/dt = d[G]/2dt = d[H]/dt
When the concentration of D is decreasing by 0.10 M/s, how fast is the concentration of H increasing:
Given data = d[D]/dt = 0.10 M/s
-d[D] / 2dt = d[H]/dt
d[H]/dt = 0.05 M/s
The concentration of H is increasing, half as fast as D decreases: 0.05 mol L–1.s–1
When the concentration of G is increasing by 0.20 M/s, how fast is the concentration of E decreasing:
d[G] / 2dt = -d[H]/3dt
E decreseas 3/2 as fast as G increases = 0.30 M/s
8. 4 grams of water will be produced.
Answer:
All the elements in one group have the same number of valence electrons. ... Since elements in a group have the same number of valence electrons, they behave similarly in chemistry. An example would be the alkali metals (excepting hydrogen. Hydrogen is in this group only because it has one valence electron.
Explanation:
Answer:
Reactant concentration, the physical states of the reactants, surface area, temperature and the presence of catalyst.
Answer:
2.05 × 10²³ formula units
Explanation:
Given data:
Mass of AgF = 43.15 g
Number of formula units = ?
Solution:
Number of moles of AgF:
Number of moles = mass/ molar mass
Number of moles = 43.15 g/ 126.87 g/mol
Number of moles = 0.34 mol
Now Number of formula units will be determine by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number
1 mole = 6.022 × 10²³ formula units
0.34 mol × 6.022 × 10²³ formula units
2.05 × 10²³ formula units
