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cestrela7 [59]
3 years ago
12

Calculate the mass, in grams, of a single tellurium atom (mte = 127.60 amu ).

Chemistry
2 answers:
UNO [17]3 years ago
8 0

1 Atomic mass unit is the mass of an atom or it caliberates mass on atomic scale. It is also expressed in dalton denoted by Da whereas Atomic mass unit is denoted by amu.

1 amu can be expressed in grams as follows:

1 amu = 1.6 * 10^-2^4 g

Mass of Te = 127.6 amu

For converting in grams,

M = (127.6 ) * 1.6 * 10^-2^4 g

M = 204.16 * 10^-2^4 g

Thus, mass of Te is 204.16 * 10^-2^4 g

trapecia [35]3 years ago
4 0

The mass, in grams, of a single tellurium atom = 2,118. 10⁻²² grams

<h3>Further explanation</h3>

Inside the atom consists of a nucleus containing 3 elementary particles, namely protons and neutrons, while electrons move around the nucleus.

Protons are positively charged (+1), electrons are negatively charged (-1). and neutrons are uncharged (neutral)

While the mass of 1 proton is equal to the mass of 1 neutron, equal to 1 amu and the electron has a mass smaller than both.

Atomic mass is the average atomic mass of all its isotopes

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom

An atomic mass unit = amu is a relative atomic mass of 1/12 the mass of an atom of carbon-12.

The 'amu' unit has now been replaced with a unit of 'u' only

The hydrogen atom is the lightest atom whose mass is 1.67 x 10⁻²⁷kg (measured using a mass spectrometer) and simplified to 1 amu (atomic mass unit).

1 amu = 1,66.10⁻²⁴ grams

For example the C-12 carbon atomic mass is 12 amu, C-13 is 13 amu

Single tellurium atoms have = 127.60 amu

So that the mass is in grams:

mass = 127.60 amu x 1.66.10⁻²⁴

mass = 2,118. 10⁻²² grams

<h3>Learn more</h3>

atomic weight of 120.9038 amu

brainly.com/question/4551913

The subatomic particle that has the least mass

brainly.com/question/2224691

element 2512X

brainly.com/question/2572495

about subatomic particles statement

brainly.com/question/3176193

Keywords: atomic mass, amu

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When 125 grams of FeO react with 25.0 grams of Al, how many grams of Fe can be produced? FeO + Al → Fe + Al2O3 25.9 g Fe 38.7 g
Serga [27]

<u>Answer:</u> The mass of iron produced will be 77.6 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For FeO:</u>

Given mass of FeO = 125 g

Molar mass of FeO = 71.8 g/mol

Putting values in equation 1, we get:

\text{Moles of FeO}=\frac{125g}{71.8g/mol}=1.74mol

  • <u>For aluminium:</u>

Given mass of aluminium = 25.0 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{25.0g}{27g/mol}=0.93mol

The given chemical reaction follows:

3FeO+2Al\rightarrow 3Fe+Al_2O_3

By Stoichiometry of the reaction:

2 moles of aluminium metal reacts with 3 mole of FeO

So, 0.93 moles of aluminium metal will react with = \frac{3}{2}\times 0.93=1.395mol of FeO

As, given amount of FeO is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium metal is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of aluminium metal produces 3 mole of iron metal

So, 0.93 moles of aluminium metal will produce = \frac{3}{2}\times 0.93=1.395moles of iron metal

  • Now, calculating the mass of iron metal from equation 1, we get:

Molar mass of iron = 55.85 g/mol

Moles of iron = 1.395 moles

Putting values in equation 1, we get:

1.395mol=\frac{\text{Mass of iron}}{55.85g/mol}\\\\\text{Mass of iron}=(1.395mol\times 55.85g/mol)=77.6g

Hence, the mass of iron produced will be 77.6 grams

4 0
4 years ago
In the early 1960s, radioactive strontium-90 was released during atmospheric testing of nuclear weapons and got into the bones o
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Answer:

52.54 %

Explanation:

Half life = 29 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{29.0}\ {years}^{-1}

The rate constant, k = 0.023902 hour⁻¹

From 1964 to 1991:

Time = 27 years

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,  

\frac {[A_t]}{[A_0]}=e^{-0.023902\times 27}

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Answer:

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volume = 62 - 52 = 10 mL

From the question we have

density =  \frac{180}{10}  \\

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<h3>18 g/mL</h3>

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