Answer:
A. 55
Step-by-step explanation:
55 + 30 + 40 + 55 = 180
I hope this helps u! :D
Here are your equations:
x and 3x
How to set up:
2(x)+ 2(3x) = 44
Simplify:
8x = 44
Divide:
x = 5.5
Plug back in to find values:
Width = 5.5
Length = 16.5
Hope this helps!! :)
There are 9 candies in total, with 5 being orange. Think of it. For the first grab, you have a 5/9 chance of it being orange flavored. Now there are 4 orange flavored candies, and 8 total candies in the bag. Grabbing a second candy, Billy has a 4/8 chance of grabbing an orange flavored candy. So your two fractions are...
5/9, 4/8
Can you combine these two fractions for a final answer?
Answer:
63-9b
Step-by-step explanation:
9(7-b)
=9×7-9×b
=63-9b
Answer: The answer is 50980
Step by Step Explanation:
First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.
