B) timing chain too loose
Answer:
Add the thermal R values of each wall layer.
Explanation:
Fiberglass insulation R value, sheetrock, sheathing, siding etc. All sum together to one composite opposition to heat transfer/loss.
Q= U x A x Delta T
Q= heat transfer btuh
U= 1/R inverse of resistance
A= area of surface
Delta T is temerature difference across the wall.
Answer:
function summedValue = SummationWithLoop(userNum)
% Summation of all values from 1 to userNum
summedValue = 0;
i = 0;
% use a while loop that assigns summedValue with the
% sum of all values from 1 to userNum
while(i <= userNum)
summedValue = summedValue + i;
i = i + 1;
end
end
<u></u>
has greater effect.
<u>Explanation</u>:
= Temperature of cold reservoir
= Temperature of hot reservoir
when 
is decreased by 't',
= 
when 
is increased by 'T'
Answer:
E=52000Hp.h
E=38724920Wh
E=1.028x10^11 ftlb
Explanation:
To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.
Finally, when you have the result Hp h / year you convert it to Ftlb and Wh
E=52000Hp.h
E=38724920Wh
E=1.028x10^11 ftlb
