Answer:
All 3 principal stress
1. 56.301mpa
2. 28.07mpa
3. 0mpa
Maximum shear stress = 14.116mpa
Explanation:
di = 75 = 0.075
wall thickness = 0.1 = 0.0001
internal pressure pi = 150 kpa = 150 x 10³
torque t = 100 Nm
finding all values
∂1 = 150x10³x0.075/2x0,0001
= 0.5625 = 56.25mpa
∂2 = 150x10³x75/4x0.1
= 28.12mpa
T = 16x100/(πx75x10³)²
∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]
= 1/2[84.37±√791.2969+5.827396]
= 1/2[84.37±28.33]
∂1 = 1/2[84.37+28.33]
= 56.301mpa
∂2 = 1/2[84.37-28.33]
= 28.07mpa
This is a 2 d diagram donut is analyzed in 2 direction.
So ∂3 = 0mpa
∂max = 56.301-28.07/2
= 14.116mpa
The weight of the specimen in SSD condition is 373.3 cc
<u>Explanation</u>:
a) Apparent specific gravity = 
Where,
A = mass of oven dried test sample in air = 1034 g
B = saturated surface test sample in air = 1048.9 g
C = apparent mass of saturated test sample in water = 975.6 g
apparent specific gravity =
= 
Apparent specific gravity = 2.88
b) Bulk specific gravity 
= 2.76
c) Bulk specific gravity (SSD):
= 2.80
d) Absorption% :
Absorption = 1.44 %
e) Bulk Volume :
= 
Answer:
When a horse pull a cart the action is on?
A horse is harnessed to a cart. If the horse tries to pull the cart, the horse must exert a force on the cart. By Newton's third law the cart must then exert an equal and opposite force on the horse. Newton's second law tells us that acceleration is equal to the net force divided by the mass of the system.
Explanation:
