All categories

3 years ago

YO CUTIE! HELP MEEEEEE! Hazardous waste is a category that includes all of the following EXCEPT

Engineering

2 answers:

sesenic [268]3 years ago

7 0

Answer:

B . Soluble

Explanation:

am i a cutie tho?

madam [21]3 years ago

3 0

your answer should be <u>B. Soluble</u>

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A fiberglass composite is composed of a matrix of vinyl ester and reinforcing fibers of E-glass. The volume fraction of E-glass

masha68 [24]

Full Question

Calculate the modulus of elasticity of the composite

I. In the longitudinal direction of the glass fibre

2. In the perpendicular direction of glass fibre

Answer:

1. 27.5876 GPa

2. 5.725 GPa

Explanation:

Given

Dimensions of the fibreglass is given by: 1.00 cm x 25.00 cm x 200.00 cm

Volume = 1 * 25 * 200 = 5000cm³

P1 = The volume fraction of the E-glass is 31%

P2 = The remainder 69% is Vinyl Ester

Volume of Vinyl Ester= 69% * 5000cm³ = 3450cm³

I. In the longitudinal direction of the glass fibre

Where

Modulus of elasticity of glass, E1 = 80 Gpa

Modulus of elasticity of vinyl ester, E2 = 4.04 Gpa

Modulus of elasticity = E1P1 + E2P2

Modulus of elasticity of vinyl esters = 31% * 80 + 69% * 4.04

Modulus = 24.8 + 2.7876

Modulus = 27.5876 GPa

ii. In the perpendicular direction of glass fibre

This is solved by

E1.E2/(P1.E2 + P2.E1)

= (80 * 4.04)/(31% * 4.04 + 69% * 80)

= 323.2/(1.2524 + 55.2)

= 5.725177317527687

= 5.725 GPa

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3 years ago

Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of "84" m3/min and exits at 12

Nina [5.8K]

Answer:

W = - 184.8 kW

Explanation:

Given data:

$P_1 = 1.05 bar$

$T_1 = 300K$

$\dot V_1 = 84 m^3/min$

$P_2 = 12 bar$

$T_2 = 400 K$

We know that work is done as

$W = - [ Q + \dor m[h_2 - h_1]]$

for $P_1 = 1.05 bar, T_1 = 300K$

density of air is 1.22 kg/m^3 and $h_1 = 300 kJ/kg$

for $P_2 = 12 bar, T_2 = 400 K$

$h_2 = 400 kj/kg$

$\dot m = \rho \times \dor v_1 = 1.22 \frac{84}{60} =1.708 kg/s$

W = -[14 + 1.708[400-300]]

W = - 184.8 kW

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3 years ago

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3 years ago

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True/False

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