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3 years ago

YO CUTIE! HELP MEEEEEE! Hazardous waste is a category that includes all of the following EXCEPT

Engineering

2 answers:

sesenic [268]3 years ago

7 0

Answer:

B . Soluble

Explanation:

am i a cutie tho?

madam [21]3 years ago

3 0

your answer should be B. Soluble

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The following is a correlation for the average Nusselt number for natural convection over spherical surface. As can be seen in t

vovikov84 [41]

Answer:

Explanation:

$r_2=$ ∞

$q=4\pi kT_1(T_2-T_1)\\$

$q=2\pi kD.$ ΔT--------(1)

$q=hA$ ΔT $=4\pi r_1^2(T_2_s-T_1_s)\\$

$N_u=\frac{hD}{k} = 2+\frac{0.589 R_a^\frac{1}{4} }{[1+(\frac{0.046}{p_r}\frac{9}{16} )^\frac{4}{9} } ------(3)$

By equation (1) and (2)

$2\pi kD.$ ΔT=h.4 $\pi r_1^2$ ΔT

$2kD=hD^2\\\frac{hD}{k} =2\\N_u=\frac{hD}{k}=2\\$ -------(4)

From equation (3) and (4)

So for sphere $R_a$ →0

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3 years ago

An ideal gas initially occupying 0.020 m3 at 1.0 MPa is quasistatically expanded inside a piston-cylinder device at a constant p

egoroff_w [7]

An ideal gas initially occupying 0.020 m3 at 1.0 MPa is quasistatically expanded inside a piston-cylinder device at a constant pressure until its volume doubles. Next the expansion is continued at constant volume till the pressure reaches half of the initial pressure. Finally it is brought back to the initial state in a polytropic process with exponent n=1.6

a. Draw the processes on a P-v diagram and calculate the total work.
b. Calculate the total heat transfered, what is the difference between the initial and final temperature?an answer is to present a question of how you are not able to join the world and how you can help please answer

8 0

3 years ago

A rigid tank contains an ideal gas at 40°C that is being stirred by a paddle wheel. The paddle wheel does 240 kJ of work on the

Sergeu [11.5K]

To solve the problem it is necessary to consider the concepts and formulas related to the change of ideal gas entropy.

By definition the entropy change would be defined as

$\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{P_2}{P_1})$

Using the Boyle equation we have

$\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{v_1T_2}{v_2T_1})$

Where,

$C_p$ = Specific heat at constant pressure

$T_1$ = Initial temperature of gas

$T_2$ = Final temprature of gas

R = Universal gas constant

$v_1$ = Initial specific Volume of gas

$v_2$ = Final specific volume of gas

According to the statement, it is an isothermal process and the tank is therefore rigid

$T_1 = T_2, v_2=v_1$

The equation would turn out as

$\Delta S = C_p ln1-ln1$

Therefore the entropy change of the ideal gas is 0

Into the surroundings we have that

$\Delta S = \frac{Q}{T}$

Where,

Q = Heat Exchange

T = Temperature in the surrounding

Replacing with our values we have that

$\Delta S = \frac{230kJ}{(30+273)K}$

$\Delta S = 0.76 kJ/K$

Therefore the increase of entropy into the surroundings is 0.76kJ/K

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3 years ago

T he area of a circle is pr 2. Define r as 5, then find the area of a circle,using MATLAB®.(b) The surface area of a sphere is 4

aksik [14]

Answer:

Area of Circle = 78.5398

Surface Area of Sphere = 1.2566 x 10^3 = 1256.6 ft

Volume of Sphere = 33.5103 ft

Explanation:

Please find below the written MatLab script used to solve the problem. I had to define r in each case to solve for the Area of the circle, the surface area and the volume of the Sphere.

r=5; % define r as 5

a=pi*r^2;% calculate the area of the circle

AreaOfCircle=a

r=10; % define r and 10 ft

sa=4*pi*r^2; %Calculate the surface area of the sphere

SphereSurfaceArea=sa

r=2;% define r as 2 ft

vs=(4/3)*pi*r^3;% Calculate the volume of the sphere

VolumeShere=vs

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3 years ago

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Ratling [72]

Answer:

hfhhfhff

Explanation:

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3 years ago