All categories

3 years ago

What is the basic molecular mechanism for polymer plasticity, and how does it differ from that of ductile crystalline metals?

Engineering

1 answer:

sdas [7]3 years ago

4 0

Answer:

In Crystalline metals or materials, plasticity is examined from the perspective of the motion of linear defects or dislocations within the polymer chains.

Explanation:

When a temperature range below and near the glass transition temperature is reached, there is warping or contortion of structureless or malformed polymers. This warping happens as the polymer chains move over one another.

Unlike elasticity when requires or enables an object to resume its original dimensions, ductility is the quality of an element or material to change form albeit permanently.

Cheers

You might be interested in

Technician A says that wheel lug nuts can be loosened when the vehicle is off the ground with an impact

Pavlova-9 [17]

Answer:

technician a is correct, if you were to torque down a wheel with an impact then you could risk damaging the wheel and over tightening the lugs

Explanation:

6 0

2 years ago

Following in each of the following three mechanisms, the crank is the input link, 1) draw vectors with labeled angles 2) write t

elena-14-01-66 [18.8K]

<u>Explanation:</u>

1. $\theta_{4}=90^{\circ}, \theta_{1}=\theta^{\circ}$ (diagram)

vector loop equation is

$\overline{R_{1}}+\overline{R_{2}}+\overline{R_{3}}=\overline{R_{4}}\\$

the exponential form,

$r_{1} e^{j \exp (0)}+r_{2} e^{j \theta_{2}}+r_{3} e^{j \theta_{3}}=r_{4} e^{j(90)}$

$e=\cos \theta+j \sin \theta$

Real part, $r_{1}+\ r_{2} \cos \theta_{2}+\ r_{3} \cos \theta_{3}=0$ (i)

Imaginary part, $0+r_{2} \sin \theta_{2}+r_{3} \sin \theta_{3}=r_{4}$ (ii)

From above equation,we get unknown variables,

Now, $\theta_{2}, \theta_{3} \& r_{4}$

If $\theta_{2}$ is given,

From (i), $\theta_{3}=\cos ^{-1}\left(\frac{-r_{1}-r_{2} \cos \theta_{2}}{r_{3}}\right)$

and from (ii), we get

$x_{4}=r_{2} \sin \theta_{2}+r_{3} \sin \left[\cos ^{-1}\left(\frac{-\gamma_{1}-r_{2} \cos \theta_{2}}{r_{3}}\right)\right]$

8 0

4 years ago

Given the circuit at the right in which the following values are used: R1 = 20 kΩ, R2 = 12 kΩ, C = 10 µ F, and ε = 25 V. You clo

agasfer [191]

Answer:

a.) I = 7.8 × 10^-4 A

b.) V(20) = 9.3 × 10^-43 V

Explanation:

Given that the

R1 = 20 kΩ,

R2 = 12 kΩ,

C = 10 µ F, and

ε = 25 V.

R1 and R2 are in series with each other.

Let us first find the equivalent resistance R

R = R1 + R2

R = 20 + 12 = 32 kΩ

At t = 0, V = 25v

From ohms law, V = IR

Make current I the subject of formula

I = V/R

I = 25/32 × 10^3

I = 7.8 × 10^-4 A

b.) The voltage across R1 after a long time can be achieved by using the formula

V(t) = Voe^- (t/RC)

V(t) = 25e^- t/20000 × 10×10^-6

V(t) = 25e^- t/0.2

After a very long time. Let assume t = 20s. Then

V(20) = 25e^- 20/0.2

V(20) = 25e^-100

V(20) = 25 × 3.72 × 10^-44

V(20) = 9.3 × 10^-43 V

8 0

3 years ago

The moisture content in air (humidity) is measured by weight and expressed in pounds or ____________________.

VikaD [51]

Moisture content is measured in terms of pounds of water per pound of air (lb water/lb air) or grains of water per pound of air (gr. of water/lb air).

Hope this helps❤

3 0

2 years ago

Which of the following describes beta testing?

Sergio039 [100]

Answer:

What is Beta Testing? Beta testing is an opportunity for real users to use a product in a production environment to uncover any bugs or issues before a general release. Beta testing is the final round of testing before releasing a product to a wide audience.

3 0

3 years ago