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hodyreva [135]
2 years ago
6

Which of the following can refer to the form of exercise that uses free weights, weight machines, resistance bands, or the weigh

t of the body to put stress on the muscles? A. Strength training B. Weight training C. Resistance training D. All of the above
Physics
1 answer:
kari74 [83]2 years ago
7 0

Answer:

option C...

resistance training is the correct answer

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Safety belts and occupant protection systems are installed to reduce the harmful effects of the force of _____ during a collisio
Phantasy [73]

To lessen the negative impacts of the force generated during a collision, safety belts and occupant protective relays are installed.

Importance of safety belts:

  • The purpose of a seat belt usually referred to as a safety belt or a safety belt, is to protect the driver or an occupant of a vehicle from a potentially dangerous movement that may occur during an accident or an abrupt stop. By minimizing the power of secondary hits with interior striking hazards, maintaining proper occupant positioning for the airbag, and preventing people from being expelled from the vehicle after an accident or if the automobile rolls over, seat belts help minimize the chance of a fatal accident in traffic collisions. When the car is moving, the passenger and the driver move together with it at the same pace.
  • The occupants continue moving at the same pace the vehicle was traveling at when it stopped if it unexpectedly stops or crashes. To stop the driver and other passengers from exiting the vehicle or contacting the interiors of the vehicle, seatbelts apply an equal and opposite force to them. Due to their crucial function in occupant safety, seatbelts are regarded as the main restraint devices.

Learn more about safety belts here:

brainly.com/question/5626690

#SPJ4

3 0
2 years ago
(i) What is the acceleration of an object between 0-4 seconds?
DENIUS [597]

Answer:

Your small tiny face

Explanation:

HIHIHIIHHI

4 0
3 years ago
A ball thrown by Ginger is moving upward through the air. Diagram A shows a box with a downward arrow. Diagram B shows a box wit
vichka [17]

As the ball is moving in air as well as we have to neglect the friction force on it

So we can say that ball is having only one force on it that is gravitational force

So the force on the ball must have to be represented by gravitational force and that must be vertically downwards

So the correct FBD will contain only one force and that force must be vertically downwards

So here correct answer must be

<em>Diagram A shows a box with a downward arrow. </em>

8 0
3 years ago
What is newton's second law<br>also give example​
neonofarm [45]

\textbf{Question:-}

What is newton's second law of motion?Also give example.

\textbf{Answer:-}

<u>Definition</u>:-

Newton's Second Law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force. ie., <u>F=ma</u>.

<u>Examples:-</u>

  • When you are kicking a ball, you are increasing the speed by applying force to it. Therefore,it accelerates.
  • If you use the same force to push a truck and push a car, the car will have more acceleration than the truck.

Derivation:-

For a body of mass 'm' , whose velocity changes from u to v in time t, when Force 'F' is applied.

=>Force∝Change in momentum/Time

=>F∝mv-mu/t

=>F∝m(v-u)/t

=>F∝ma

=>F=kma(a=v-u/t)

=>F=ma(Since k=constant=1)

8 0
3 years ago
Read 2 more answers
Say that you are in a large room at temperature TC = 300 K. Someone gives you a pot of hot soup at a temperature of TH = 340 K.
Sliva [168]

To solve the problem it is necessary to take into account the concepts related to energy efficiency in the engines, the work done, the heat input in the systems, the exchange and loss of heat in the soupy the radius between the work done the lost heat ( efficiency).

By definition the efficiency of the heat engine is

\epsilon = 1- \frac{T_c}{T_h}

Where,

T_c = Temperature at the room

T_h  =Temperature of the soup

The work done is defined as,

dW = \epsilon(dQ_h)

Where Q_h represents the input heat and at the same time is defined as

dQ_h =c_v (dT_h)

Where,

c_V =Specific Heat

The change at the work would be defined then as

dW = \epsilon(dQ_h)

dW = \epsilon c_v (dT_h)

dW = (1-\frac{T_c}{T_h})c_v (dT_h)

W = \int dW = \int (1-\frac{T_c}{T_h})c_v (dT_h)

W = c_v (T_h-T_c)-c_v T_c ln(\frac{T_h}{T_c})

On the other hand we have that the heat lost by the soup is equal to

dQ_h =c_v (dT_h)

Q_h =c_v (T_h-T_c)

The ratio between both would be,

\frac{W}{Q_h} = \frac{c_v (T_h-T_c)-c_v T_c ln(\frac{T_h}{T_c})}{c_v (T_h-T_c)}

\frac{W}{Q_h} = \frac{1+ln(\frac{T_h}{T_c})}{1-\frac{T_h}{T_c}}

Replacing with our values we have,

\frac{W}{Q_h} = 1+\frac{ln(\frac{340K}{300K})}{1-\frac{340K}{300K}}

\frac{W}{Q_h} = 0.0613

Therefore the fraction of heat lost by the soup that can be turned into useable work by the engine is 0.0613.

5 0
3 years ago
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