Answer:
Work out = 28.27 kJ/kg
Explanation:
For R-134a, from the saturated tables at 800 kPa, we get
= 171.82 kJ/kg
Therefore, at saturation pressure 140 kPa, saturation temperature is
= -18.77°C = 254.23 K
At saturation pressure 800 kPa, the saturation temperature is
= 31.31°C = 304.31 K
Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.
Thus, 
= = 171.82 kJ/kg
We know COP of heat pump
COP = 
= 
= 6.076
Therefore, Work out put, W = 
= 171.82 / 6.076
= 28.27 kJ/kg
Answer:
That the universe (the balloon for this case) is expanding and that is the reason why the galaxies (the dots) appear to move away one from another.
Explanation:
By means of looking at the spectra of galaxies, it can confirm that they are moving away in an accelerated motion.
Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when it is moving away from the observer (that is known as the Doppler effect). The source in this particular case is represented for each of the galaxies.
Hence, the redshift represents this shift of the spectral lines to red part in the spectrum of a galaxy or any object which is moving away. That is a direct confirmation of how the universe is in an expanding accelerated motion.
The redshift can be define in analitic way by trought the doppler velocity:
(1)
Where 
is the wavelength shift, 
is the wavelength at rest, v is the velocity of the source and c is the speed of light.
(2)
Where z is the redshift.
The ballon example, once that it is inflating, represents how is the universe which it is expanding and that is the reason why the galaxies (the dots) appear to move away one from another.
Object weight varues on cellestial bodies due to the acceleration due to gravity acting on the body. the acc due to gravuty depend on the mass and radius of the cellestial body. Thus the weight varies on cellestian bodies
Answer:
The magnitude of the vector A is <u>51 m.</u>
Explanation:
Given:
The horizontal component of a vector A is given as:
The vertical component of a vector A is given as:
Now, we know that, a vector A can be resolved into two mutually perpendicular components; one along the x axis and the other along the y axis. The magnitude of the vector A can be written as the square root of the sum of the squares of each component.
Therefore, the magnitude of vector A is given as:
Now, plug in 44.4 for 
, 25.1 for 
and solve for the magnitude of A. This gives,
Therefore, the magnitude of the vector A is 51 m.
