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polet [3.4K]
4 years ago
11

Using Newton's third law of motion, explain what happens when you let an untied balloon go.

Physics
2 answers:
mash [69]4 years ago
7 0

Answer:

balloon pushes you back

Explanation:

3rd Law: Every action has an equal and opposite reaction

So, when you let go of the balloon it's pushed forward so the balloon pushes you back

Lunna [17]4 years ago
7 0
It’s floats up into the air
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Given (kg/s) (m/s) , what is the resulting unit?
postnew [5]

I think you mean for those fractions to be multiplied.
In that case, you get

                   kg - m / sec²  =  Newton .

7 0
3 years ago
A cube icebox of side 3cm has a thickness of 5.0cm. If 4.0 kg of ice is put in the box estimate the amount of ice remaining afte
qaws [65]

Answer:

The amount of solid ice remaining after 6 hours is approximately 3.68664 kg

Explanation:

The given parameters are;

The side length of the cube box, s = 3(0) cm = 0.3 m

The thickness of the cube box, d = 5.0 cm = 0.05 m  

The mass of ice in the box, m = 4.0 kg

The outside temperature of the cube box, T₁ = 45°C

The temperature of the melting ice inside the box, T₂ = 0°C

The latent heat of fusion of ice, L_f = 3.35 × 10⁵ J/K/hr/kg

The surface area of the box, A = 6·s² 6 × (0.3 m)² = 0.54 m²

The coefficient of thermal conductivity, K = 0.01 J/s·m⁻¹·K⁻¹

For thermal equilibrium, we have;

The heat supplied by the surrounding = The heat gained by the ice

The  heat supplied by the surrounding, Q = K·A·ΔT·t/d

Where;

ΔT = T₁ - T₂ =  45° C - 0° C = 45° C

ΔT = 45° C

Q = K·A·ΔT·t/d = 0.01 × 0.54 × 45 × 6× 60×60/0.05 = 104976

∴ The  heat supplied by the surrounding, Q = 104976 J

The heat gained by the ice = L_f × m_{melted \ ice} =3.35 × 10⁵ J/kg × m_{melted \ ice}

Therefore, from Q =  L_f × m_{melted \ ice}, we have;

Q = 104976 J =  L_f × m_{melted \ ice} = 3.35 × 10⁵ J/kg × m_{melted \ ice}

104976 J = 3.35 × 10⁵ J/kg × m_{melted \ ice}

m_{melted \ ice} = 104976 J/(3.35 × 10⁵ J/kg) ≈ 0.31336 kg

The mass of melted ice, m_{melted \ ice} ≈ 0.31336 kg

∴ The amount of solid ice remaining after 6 hours, m_{ice} = m - m_{melted \ ice}

Which gives;

m_{ice} = m - m_{melted \ ice} = 4.0 kg - 0.31336 kg ≈ 3.68664 kg

The amount of solid ice remaining after 6 hours, m_{ice} ≈ 3.68664 kg.

8 0
3 years ago
Molecular homologies include similarities between all of the following except ___________.
dezoksy [38]

Answer:

Punctuated sedimentation

Explanation:

Punctuated sedimentation isn't part of the molecular homologies or the theory of molecules

6 0
4 years ago
Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by 0.1
ludmilkaskok [199]

Answer:

1.189eV

Explanation:

The electric potential energy is the potential energy that results from the Coulomb force and is associated with the configuration of two or more charges. For an electron in the presence of an electric field produced by a proton, the electric potential energy is defined as:

U=\frac{kq_{e}q_{p}}{r}

where  q_{e} is the electron charge, q_{p} is the proton charge, r is the separation distance between the charges and k is the coulomb constant.

Knowing this, we can calculate how much electric potential energy was lost:

\Delta U=U_{f}-U{i}\\\Delta U=\frac{kq_{e}q_{p}}{r_{f}}-\frac{kq_{e}q_{p}}{r_{i}}\\\Delta U=kq_{e}q_{p}(\frac{1}{r_{f}}-\frac{1}{r_{i}})\\\Delta U=(8.99*10^9\frac{Nm^2}{C^2})(-1.60*10^{-19}C)(1.60*10^{-19}C)(\frac{1}{0.105*10^{-9}m}-\frac{1}{0.115*10^{-9}m})\\\Delta U=1.90*10^{-19}J*\frac{6.2415*10^{18}eV}{1J}=1.189eV

5 0
4 years ago
A spaceship is traveling at 24,000 m/sec. At T=5 sec, the rocket trusts are turned on. At T=55 sec, the spaceship reaches a spee
slava [35]

Answer:

<em>480m/s²</em>

Explanation:

Acceleration is the change in velocity of a body with respect to time;

Acceleration = change in velocity/change in time

change in velocity = 29,500 - 24,000

change in velocity= 5,500

Change in time = 55 - 5

change in time = 50secs

Substitute into the formula;

spaceships acceleration = 24000/50

spaceships acceleration = 480 m/s²

<em>Hence the spaceships acceleration is 480m/s²</em>

8 0
3 years ago
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