When a force acts on a body along some path, the work done is W=F*s, where W is the work done, F is the force that is doing the work on the body and s is the path. The force doing the work has to be in the same direction, or parallel, as the path. This is called positive work. If the force and the path are anti-parallel, the work is negative. So the relationship between work and force is W=F*s.
Answer:
glucose
Explanation:
convert starch to glucose
Answer:
Tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s
Explanation:
From the question above,
(1) tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s
Mometum = mass×velocity
Momentum = 270×0.5
Momentum = 135 kgm/s
(2) hare with a mass of 2.7 kg moving at a velocity of 7 m/s
Mementum = mass × velocity
Momentum = 2.7×7
Momentum = 18.9 kgm/s
(3) turtle with a mass of 91 kg moving at a velocity of 1.4 m/s
Momentum = mass × velocity
Momentum = 91×1.4
Momentum = 127.4 kgm/s
(4) roadrunner with a mass of 1.8 kg moving at a velocity of 6.7 m/s
Momentum = mass × velocity
Momentum = 1.8×6.7
Momentum = 12.06 kgm/s
From the above, the one with the greatest momentum is tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s
Answer:
-1786.5J
Explanation:
Temperature 1=T1=25°c
Temperature 2=T2=200°c
Pressure P1=1bar
Pressure P2=0.5bars
T=37°c+273=310k
Note number if moles=1
Recall work done =2.3026RTlogp2/P1
2.3026*8.314*310log(0.5/1)
-1786.5J
Answer:
5.3 cm
Explanation:
This question is an illustration of real and apparent distance.
From the question, we have the following given parameters
Real Distance, R = 8.0cm
Refractive Index, μ = 1.5
Required
Determine the apparent distance (A)
The relationship between R, A and μ is:
μ = R/A
i.e.
Refractive Index = Real Distance ÷ Apparent Distance
Substitute values in the above formula
1.5 = 8/A
Multiply both sides by A
1.5 * A = A * 8/A
1.5A = 8
Divide both side by 1.5
1.5A/1.5 = 8/1.5
A = 8/1.5
A = 5.3cm
Hence, the letters would appear at a distance of 5.3cm
