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2 years ago

How does wind help you to know gases are matter

Physics

1 answer:

frozen [14]2 years ago

5 0

Wind has mass. Anything with mass is also matter. Sound good?

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2 Points<br> Electrons are——<br> charged particles.

Ierofanga [76]

Answer:

Electrons are negatively charged particles

5 0

3 years ago

Read 2 more answers

You are playing catch with a friend in a moving train. When you toss the ball in the direction the train is moving, how does the

S_A_V [24]

I think to an observer outside the train, the speed of the ball will actually look like more than the speed of the train.

4 0

3 years ago

Jimothy is riding his bike to his friend's house. He decides to see how fast he can go, and starts pedaling as hard as he can. H

german

Answer:

Final velocity, V = 11.5m/s

Explanation:

Given the following data;

Initial velocity, U = 2.5m/s

Acceleration, a = 1.5m/s²

Time, t = 6secs

To find the final velocity, we would use the first equation of motion

V = U + at

Substituting into the equation, we have

V = 2.5 + 1.5*6

V = 2.5 + 9

Final velocity, V = 11.5m/s

6 0

3 years ago

A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity = 4.184 J/g K) at initial temperatur

BARSIC [14]

Answer : The molar heat of solution for the salt is 452.9 kJ/mole

Explanation :

First we have to calculate the heat of solution.

$q=m\times c\times \Delta T$

where,

q = heat of solution = ?

c = specific heat of water = specific heat of solution = $4.184J/g.K=4.184J/g^oC$

m = mass of solution = 107.093 g

Mass of solution = Mass of water + Mass of salt
Mass of solution = 100.000 g + 7.093 g = 107.093 g

$\Delta T$ = change in temperature = $T_2-T_1=(80.000-61.128)=18.872^oC=$

Now put all the given values in the above formula, we get:

$q=107.093g\times 4.184J/g^oC\times 18.872^oC$

$q=8456.111J=8.456kJ$

Now we have to calculate the molar heat of solution for the salt, in kJ/mol.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = molar heat of solution = ?

q = heat required = 8.456 kJ

m = mass of salt = 7.093 g

Molar mass of salt = 379.984 g/mol

$\text{Moles of salt}=\frac{\text{Mass of salt}}{\text{Molar mass of salt}}=\frac{7.093g}{379.984g/mole}=0.01867mole$

$\Delta H=\frac{8.456kJ}{0.01867mole}=452.9kJ/mole$

Therefore, the molar heat of solution for the salt is 452.9 kJ/mole

4 0

3 years ago

A Goodyear blimp typically contains 5400 m³ of helium (He) at an absolute pressure of 1.10 × 10 5 1.10 × 10 5 Pa. The temperatur

Wewaii [24]

The concept related to this exercise to solve this problem is the ideal Gas law which establishes

$PV = nRT$

P= Pressure

V= Volume

n = Number of moles

R= Gas ideal Constant

T= Temperature

Our values are given as,

$V =5400m^3 \\P = 1.1*10^5Pa\\T = 295K \\M_m =4.0026g\\R = 8.3145J\cdot mol^{-1}K^{-1}\\$

From the ideal gas equation then we rearrange the equation to obtain the number of moles, then

$PV=nRT\\n = \frac{PV}{RT}\\n= 242174.43$

By definition the molecular mass (n) is expressed in terms of the mass and molecular weight therefore

$n = \frac{m}{M_m}$

$m = n*M_m$

$m = (242174.43)(4.0026)n$

$m = 969327.37$

$m = 968.327Kg$

Therefore the mass of the helium in the blimp is 968.327Kg

4 0

3 years ago