Volume of a sphere and a cone
We have that the equation of the volume of a sphere is given by:

We have that the radius of a sphere is half the diameter of it:
Then, the radius of this sphere is
r = 6cm/2 = 3cm
<h2>Finding the volume of a sphere</h2>
We replace r by 3 in the equation:

Since 3³ = 3 · 3 · 3 = 27

If we use π = 3.14:

Rounding the first factor to the nearest hundredth (two digits after the decimal), we have:
4.18666... ≅ 4.19
Then, we have that:

Then, we have that:
<h2>Finding the volume of a cone</h2>
We have that the volume of a cone is given by:

where r is the radius of its base and h is the height:
Then, in this case
r = 3
h = 6
and
π = 3.14
Replacing in the equation for the volume:

Then, we have:
3² = 9

Answer: the volume of the cone that has the same circular base and height is 56.52 cm³
The answer to 12x23 is 276
The answer should be 3 hours and 45 minutes if i did the math in my head correctly
Answer: the percent of the students at this university are foreign = 30%
Step-by-step explanation:
Given: Probability that college students are foreign students who also smoke: P(S|F)=0.12
Probability that foreign college students smoke P(S∩F)=0.4
The probability that the students at this university are foreign :
[By conditional probability formula]

Hence, the percent of the students at this university are foreign = 30%